Engineering Mechanics The velocity of a body on reaching the ground from a height h, is 2g.√h 2.√(gh) √(gh) √(2gh) 2g.√h 2.√(gh) √(gh) √(2gh) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Which of the following statement is incorrect? A force acting in the opposite direction to the motion of the body is called force of friction The ratio of the limiting friction to the normal reaction is called coefficient of friction A machine whose efficiency is 100% is known as an ideal machine The velocity ratio of a machine is the ratio of load lifted to the effort applied A force acting in the opposite direction to the motion of the body is called force of friction The ratio of the limiting friction to the normal reaction is called coefficient of friction A machine whose efficiency is 100% is known as an ideal machine The velocity ratio of a machine is the ratio of load lifted to the effort applied ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics If the body falls freely under gravity, then the gravitational acceleration is taken as +8.9 m/s2 -8.9 m/s2 +9.8 m/s2 -9.8 m/s2 +8.9 m/s2 -8.9 m/s2 +9.8 m/s2 -9.8 m/s2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The static friction All of these Is independent of the area of contact, between the two surfaces Bears a constant ratio to the normal reaction between the two surfaces Always acts in a direction, opposite to that in which the body tends to move All of these Is independent of the area of contact, between the two surfaces Bears a constant ratio to the normal reaction between the two surfaces Always acts in a direction, opposite to that in which the body tends to move ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG / Ah2 IP = IG + Ah2 IP = IG - Ah2 IP = Ah2 / IG IP = IG / Ah2 IP = IG + Ah2 IP = IG - Ah2 IP = Ah2 / IG ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics When a body of mass 'm' attains a velocity 'v' from rest in time 't', then the kinetic energy of translation is mgv2 0.5 mv2 mv2 0.5 mgv2 mgv2 0.5 mv2 mv2 0.5 mgv2 ANSWER DOWNLOAD EXAMIANS APP
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