Engineering Mechanics Two like parallel forces are acting at a distance of 24 mm apart and their resultant is 20 N. It the line of action of the resultant is 6 mm from any given force, the two forces are 15 N and 15 N None of these 15 N and 5 N 20 N and 5 N 15 N and 15 N None of these 15 N and 5 N 20 N and 5 N ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to Newton's first law of motion, Everybody continues in its state of rest or of uniform motion, in a straight line, unless it is acted upon by some external force To every action, there is always an equal and opposite reaction The rate of change of momentum is directly proportional to the impressed force, and takes place in the same direction, in which the force acts None of these Everybody continues in its state of rest or of uniform motion, in a straight line, unless it is acted upon by some external force To every action, there is always an equal and opposite reaction The rate of change of momentum is directly proportional to the impressed force, and takes place in the same direction, in which the force acts None of these ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The ratio of static friction to dynamic friction is always None of these Greater than one Equal to one Less than one None of these Greater than one Equal to one Less than one ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Moment of inertia of a circular section about its diameter (d) is πd4/32 πd3/32 πd4/64 πd3/16 πd4/32 πd3/32 πd4/64 πd3/16 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The Cartesian equation of trajectory is (where u = Velocity of projection, α = Angle of projection, and x, y = Co-ordinates of any point on the trajectory after t seconds.) y = (gx²/2u² cos²α) - x. tanα y = x. tanα + (gx²/2u² cos²α) y = x. tanα - (gx²/2u² cos²α) y = (gx²/2u² cos²α) + x. tanα y = (gx²/2u² cos²α) - x. tanα y = x. tanα + (gx²/2u² cos²α) y = x. tanα - (gx²/2u² cos²α) y = (gx²/2u² cos²α) + x. tanα ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The maximum efficiency of a screw jack is (1 - tanφ)/(1 + tanφ) (1 - sinφ)/(1 + sinφ) (1 + sinφ)/(1 - sinφ) (1 + tanφ)/(1 - tanφ) (1 - tanφ)/(1 + tanφ) (1 - sinφ)/(1 + sinφ) (1 + sinφ)/(1 - sinφ) (1 + tanφ)/(1 - tanφ) ANSWER DOWNLOAD EXAMIANS APP
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