Hydraulics and Fluid Mechanics in ME The velocity at which the flow changes from laminar flow to turbulent flow is called Velocity of approach Super-sonic velocity Sub-sonic velocity Critical velocity Velocity of approach Super-sonic velocity Sub-sonic velocity Critical velocity ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME A streamline is defined as the line of equal yelocity in a flow parallel to outer surface of pipe along which the pressure drop is uniform parallel to central axis flow of equal yelocity in a flow parallel to outer surface of pipe along which the pressure drop is uniform parallel to central axis flow ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME In one dimensional flow, the flow Takes place in curve Takes place in straight line Is steady and uniform Takes place in one direction Takes place in curve Takes place in straight line Is steady and uniform Takes place in one direction ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The hammer blow in pipes occurs when The flow of fluid through the pipe is suddenly brought to rest by closing of the valve There is excessive leakage in the pipe The pipe bursts under high pressure of fluid The flow of fluid through the pipe is gradually brought to rest by closing of the valve The flow of fluid through the pipe is suddenly brought to rest by closing of the valve There is excessive leakage in the pipe The pipe bursts under high pressure of fluid The flow of fluid through the pipe is gradually brought to rest by closing of the valve ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME When the coefficient of discharge (Cd) is 0.623, then the general equation for discharge over a rectangular weir is 1.84(L - 0.1nH)H5/2 1.84(L - nH)H3 1.84(L - nH)H2 1.84(L - 0.1nH)H3/2 1.84(L - 0.1nH)H5/2 1.84(L - nH)H3 1.84(L - nH)H2 1.84(L - 0.1nH)H3/2 ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The discharge over a rectangular weir, considering the velocity of approach, is (whereH1 = H + Ha = Total height of water above the weir, H = Height of water over the crest of the weir, and Ha = Height of water due to velocity of approach) (2/3) Cd × L.√2g [H1 - Ha] (2/3) Cd × L.√2g [H12 - Ha2] (2/3) Cd × L. √2g [H13/2 - Ha3/2] (2/3) Cd × L. √2g [H15/2 - Ha5/2] (2/3) Cd × L.√2g [H1 - Ha] (2/3) Cd × L.√2g [H12 - Ha2] (2/3) Cd × L. √2g [H13/2 - Ha3/2] (2/3) Cd × L. √2g [H15/2 - Ha5/2] ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS