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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
The smallest number which when divided by 20, 25, 35 and 40 leaves a remainder of 14, 19, 29 and 34 respectively is?

1496
1494
1349
1994

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:

107
111
185
101

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

 Let the numbers be 37a and 37b.Then, 37a x 37b = 4107 ab = 3.Now, co-primes with product 3 are (1, 3).So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111). Greater number = 111.

Problems on H.C.F and L.C.M
The H.C.F and L.C.M of two numbers are 11 and 385 respectively. If one number lies between 75 and 125 , then that number is

77
99
88
110

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The greatest number that exactly divided 105, 1001 and 2436 is

3
21
11
7

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The maximum number of students among them 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is:

91
1001
910
1911

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The H.C.F. and L.C.M. of two numbers are 12 and 5040 respectively If one of the numbers is 144, find the other number

110
180
420
360

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Product of 2 numbers = product of their HCF and LCM144 * x = 12 * 5040x = (12*5040)/144 = 420

MORE MCQ ON Problems on H.C.F and L.C.M

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