Problems on H.C.F and L.C.M The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is: 107 101 111 185 107 101 111 185 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numbers be 37a and 37b.Then, 37a x 37b = 4107 ab = 3.Now, co-primes with product 3 are (1, 3).So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111). Greater number = 111.
Problems on H.C.F and L.C.M LCM of 1/3, 5/6, 5/4, 10/7 is: 10/7 10 10/11 11/10 10/7 10 10/11 11/10 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Six bells commence tolling together and toll at the intervals of 2,4,6,8,10,12 seconds resp. In 60 minutes how many times they will toll together. 31 17 21 24 31 17 21 24 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 2-4-6-8-10-12 is 120 seconds, that is 2 minutes.Now 60/2 = 30Adding one bell at the starting it will 30+1 = 31
Problems on H.C.F and L.C.M Three numbers are in the ratio 1 : 2 : 3 and their H.C.F is 12. The numbers are 5, 10, 15 12, 24, 36 10, 20, 30 4, 8, 12 5, 10, 15 12, 24, 36 10, 20, 30 4, 8, 12 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The smallest number which when diminished by 7, is divisible 12, 16, 18, 21 and 28 is: 689 1015 432 268 689 1015 432 268 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = (L.C.M. of 12,16, 18, 21, 28) + 7= 1008 + 7= 1015
Problems on H.C.F and L.C.M Two numbers are in the ratio 3 : 4. If their L.C.M. is 96. what is sum of the numbers? 56 48 84 76 56 48 84 76 ANSWER DOWNLOAD EXAMIANS APP
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