Problems on H.C.F and L.C.M The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is: 107 185 101 111 107 185 101 111 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numbers be 37a and 37b.Then, 37a x 37b = 4107 ab = 3.Now, co-primes with product 3 are (1, 3).So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111). Greater number = 111.
Problems on H.C.F and L.C.M Find the largest number of four digits which is exactly divisible by 27,18,12,15 11720 8720 10720 9720 11720 8720 10720 9720 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 27-18-12-15 is 540.After dividing 9999 by 540 we get 279 remainder.So answer will be 9999-279 = 9720
Problems on H.C.F and L.C.M Six belts commence tolling together and toll at intervals of 2, 4, 6, 8, 10 and 12 seconds respectively. In 30 minutes. how many times do they toll together ? 15 16 4 10 15 16 4 10 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The maximum number of student amoung them 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is : 1001 1911 91 910 1001 1911 91 910 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the least number of five digits which is exactly divisible by 12, 15 and 18? 11080 1080 10025 10080 11080 1080 10025 10080 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Two numbers 4242 and 2903 when divided by a certain number of three digits, leave the same remainder. Find the number? 103 113 101 107 103 113 101 107 ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS