Problems on H.C.F and L.C.M The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is: 185 107 111 101 185 107 111 101 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numbers be 37a and 37b.Then, 37a x 37b = 4107 ab = 3.Now, co-primes with product 3 are (1, 3).So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111). Greater number = 111.
Problems on H.C.F and L.C.M The smallest number which when divided by 20, 25, 35 and 40 leaves a remainder of 14, 19, 29 and 34 respectively is? 1349 1496 1994 1494 1349 1496 1994 1494 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Two numbers 4242 and 2903 when divided by a certain number of three digits, leave the same remainder. Find the number? 101 107 113 103 101 107 113 103 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Six bells commence tolling together and toll at the intervals of 2,4,6,8,10,12 seconds resp. In 60 minutes how many times they will toll together. 24 21 17 31 24 21 17 31 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 2-4-6-8-10-12 is 120 seconds, that is 2 minutes.Now 60/2 = 30Adding one bell at the starting it will 30+1 = 31
Problems on H.C.F and L.C.M Find the least number of five digits which is exactly divisible by 12, 15 and 18? 10080 11080 10025 1080 10080 11080 10025 1080 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the greatest number that will divided 43,91 and 183 so as to leave the same remainder in each case 4 7 9 13 4 7 9 13 ANSWER DOWNLOAD EXAMIANS APP
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