Area Problems The perimeter of an equilateral triangle is 90 cm. Find its area. 250?3 sq cm 151?3 sq cm 135?3 sq cm 225?3 sq cm 250?3 sq cm 151?3 sq cm 135?3 sq cm 225?3 sq cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given that, perimeter = 90 cm? 3a = 90 cm [a = side]? a = 90/3 = 30 cm? Area = ?3a2 / 4 = ?3/4 x (30)2= 900 x ?3/4 = 225?3 sq cm
Area Problems The difference between the circumference and the radius of a circle is 37 cm. The area of a circle is? 111 sq. cm 154 sq. cm 259 sq. cm 148 sq. cm 111 sq. cm 154 sq. cm 259 sq. cm 148 sq. cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP ? 2?r - r = 37? [(2 x 22/7) -1]r= 37? 37r / 7= 37? r = 7 So, area of the circle =(22/7) x 7 x 7 cm2= 154 cm2
Area Problems If area of a square is 64 sq cm, then find the area of the circle formed by the same perimeter. 215/? sq cm 216/? sq cm 256/? sq cm 318/? sq cm 215/? sq cm 216/? sq cm 256/? sq cm 318/? sq cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of square = 64 sq cm (Side)2 = 64 ? Side = ?64 = 8 cmAccording to the question,? 2?r = 4 x 8 ? r = (4 x 8)/2?? r = 16/?? Area of the circle = ? x (16/?) x (16/?) sq cm = 256/? sq cm.
Area Problems The length of a rectangular field is 100 m and its breadth is 40 m. What will be the area of the field? (4 x 103) sq m (4 x 104) sq m (4 x 10) sq m (4 x 102) sq m (4 x 103) sq m (4 x 104) sq m (4 x 10) sq m (4 x 102) sq m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required area = Length x Breadth= 100 x 40 = 4000 sq m= 4 x 103 sq m
Area Problems The radius of the wheel of a vehicle is 70 cm. The wheel makes 10 revolutions in 5 seconds. The speed of the vehicle is? 29.46 km/hr. 32.72 km/hr. 36.25 km/hr. 31.68 km/hr. 29.46 km/hr. 32.72 km/hr. 36.25 km/hr. 31.68 km/hr. ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Circumference = 2?r = 2 x (22 / 7) x 70 cm = 440 cm Distance travelled in 10 revolutions = 440 x 10 cm = 4400 cm = 44 m? Speed = distance / time= 44 / 5 m/sec= (44 / 5) x (18 / 5) km/hr = 31.68 km/hr
Area Problems The circumference of a circle is 25 cm. Find the side of the square incribed in the circle. 25/??2 cm 23/??2 21/??3 cm 29/??3 cm 25/??2 cm 23/??2 21/??3 cm 29/??3 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Circumference of the circle = 2?r = 25? r = 25 / (2?)According to the formula,Side of inscribed square = r?2 = 25 / (2?r x ?2) = 25 / (??2 ) cm
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