Area Problems The area of the sector of a circle, whose radius is 12 meters and whose angle at the centre is 42, is? 79.2 sq. meters 26.4 sq. meters 39.6 sq. meters 52.8 sq. meters 79.2 sq. meters 26.4 sq. meters 39.6 sq. meters 52.8 sq. meters ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of the sector = [(22/7) x 12 x 12] x [42°/360°] m2 = 52.8 m2
Area Problems The length of a room is 5.5 m and width is 3.75 m. Find the cost of paying the floor by slabs at the rate of Rs. 800 per sq.metre. Rs.17500 Rs.18500 Rs.16500 Rs.15500 Rs.17500 Rs.18500 Rs.16500 Rs.15500 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area = 5.5 × 3.75 sq. metre. Cost for 1 sq. metre. = Rs. 800 Hence total cost = 5.5 × 3.75 × 800 = 5.5 × 3000 = Rs. 16500
Area Problems A park of 10 meters long and 8 meters broad. What is the length of the longest pole that can be placed in the park? 13.4 metres 12.8 metres 18 metres 10 metres 13.4 metres 12.8 metres 18 metres 10 metres ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Length of the longest pole = ? [(10)2 + (8)2] m = ? 164 m = 12.8 m
Area Problems The area of sector of a circle of radius 5 cm, formed by an arc of length 3.5 cm is? 17.5 sq.cms 8. 75 sq.cms 35 sq.cms 55 sq.cms 17.5 sq.cms 8. 75 sq.cms 35 sq.cms 55 sq.cms ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of sector = ( arc length x radius ) / 2 cm2= (3.5 x 5 ) / 2= 8.75 cm2
Area Problems A circular road runs rounds a circular ground. If the difference between the circumference of the outer circle and the inner circle is 66 meters, the width of the road is? 21 meters 5.25 meters 7 meters 10.5 meters 21 meters 5.25 meters 7 meters 10.5 meters ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let outer radius be R and inner radius be r.Then from question 2?R - 2?r = 66? 2? (R-r) = 66? (2 x 22)/7 x (R - r) = 66? (R-r) = (66 x 7) / 44= 10.5 m
Area Problems The area of a right angled triangle is 10 sq cm. If its perpendicular is equal to 20 cm, find its base. 3 cm 1 cm 2 cm 4 cm 3 cm 1 cm 2 cm 4 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given that, area = 10 sq cm, perpendicular = 20 cm and base = ? area = (base x Perpendicular) / 2 ? 10 = (base x 20) / 2 ? base = 1 cm
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