Area Problems A wire can be bent in the form of a circle of radius 56cm. If it is bent in the form of a square, then its area will be 5544 4444 7744 8844 5544 4444 7744 8844 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP length of wire = 2 ?r = 2 x (22/7 ) x 56 = 352 cmside of the square = 352/4 = 88cmarea of the square = 88 x 88 = 7744sq cm
Area Problems A circle and a square have same area. The ratio of the side of the square and the radius of the circle is? ? : 1 1 : ?? 1 : ? ?? : 1 ? : 1 1 : ?? 1 : ? ?? : 1 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP ? Area of square = Area of circle ? x2 = ?r2? x/r = ?? = ? ? : 1
Area Problems The area of sector of a circle of radius 5 cm, formed by an arc of length 3.5 cm is? 55 sq.cms 8. 75 sq.cms 35 sq.cms 17.5 sq.cms 55 sq.cms 8. 75 sq.cms 35 sq.cms 17.5 sq.cms ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of sector = ( arc length x radius ) / 2 cm2= (3.5 x 5 ) / 2= 8.75 cm2
Area Problems The ratio of the area of the circumcircle and the incircle of a square is 2 : 1 1 : 2 1 : ?2 ?2 : 1 2 : 1 1 : 2 1 : ?2 ?2 : 1 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Ratio of the areas of the circumcircle and incircle of a square = [(Diagonal)2?] / [(Side)2?]= [(Side x ?2)2] / (Side)2 = 2/1 or 2 : 1
Area Problems The diagonals of a squares is 4?2 cm. The diagonal of another square whose area is double that of the first square is 6 cm 4?2 cm 8?2 cm 8 cm 6 cm 4?2 cm 8?2 cm 8 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Diagonal of square = ?2a [a = side]4?2 = ?2 a a = 4 cmNow, area of square = a2 = (42) = 16Side of a square whose area is 2 x 16.a12 = 32 ? a1 = ?32 ?a14?2Now, diagonal of new square = ?2a = ?2x 4 ?2 = 8 cm
Area Problems The length of hall is (4/3) times its breadth. If the area of hall be 300 square meters, the difference between the length and the breadth is? 15 meters 4 meters 3 meters None of these 15 meters 4 meters 3 meters None of these ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let breadth = b meters.Then, length = 4b/3 meters.? b x 4b/3 = 300? b2 = 300 x 3/4 ? b2 = 225? b = 15Hence, required difference = [(Length) - (Breadth) ]= 4b/3 - b = b/3= 15/3 m= 5 m
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