RCC Structures Design The minimum cube strength of concrete used for a pre-stressed member, is 250 kg/cm² 150 kg/cm² 50 kg/cm² 350 kg/cm² 250 kg/cm² 150 kg/cm² 50 kg/cm² 350 kg/cm² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If L is the effective span of a R.C.C. beam which is subjected to maximum shear qmax at the ends, the distance from either end over which stirrups for the shear, are provided, is (L/2) (1 - 5/qmax) (L/2) (1 - 3/qmax) (L/3) (1 - 5/qmax) (L/2) (1 - 2/qmax) (L/2) (1 - 5/qmax) (L/2) (1 - 3/qmax) (L/3) (1 - 5/qmax) (L/2) (1 - 2/qmax) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Top bars are extended to the projecting parts of the combined footing of two columns L distance apart for a distance of Half the distance of projection 0.1 L from the centre edge of column 0.1 L from the outer edge of column One-fourth the distance of projection Half the distance of projection 0.1 L from the centre edge of column 0.1 L from the outer edge of column One-fourth the distance of projection ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design High strength concrete is used in pre-stressed member All listed here To overcome high bearing stresses developed at the ends To overcome bursting stresses at the ends To provide high bond stresses All listed here To overcome high bearing stresses developed at the ends To overcome bursting stresses at the ends To provide high bond stresses ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the length of a combined footing for two columns l meters apart is L and the projection on the left side of the exterior column is x, then the projection y on the right side of the exterior column, in order to have a uniformly distributed load, is (where x̅ is the distance of centre of gravity of column loads). y = L/2 - (l + x̅) y = L/2 + (l - x̅) y = L - (l - x̅) y = L/2 - (l - x̅) y = L/2 - (l + x̅) y = L/2 + (l - x̅) y = L - (l - x̅) y = L/2 - (l - x̅) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Based on punching shear consideration, the overall depth of a combined footing under a column A, is (Perimeter of column A × Safe punching stress)/(Load on column A × Upward pressure × Area of the column) (Area of the column A × Safe punching stress)/Load on column A None of these (Perimeter of column A × Safe punching stress)/(Load on column A + Upward pressure × Area of the column) (Perimeter of column A × Safe punching stress)/(Load on column A × Upward pressure × Area of the column) (Area of the column A × Safe punching stress)/Load on column A None of these (Perimeter of column A × Safe punching stress)/(Load on column A + Upward pressure × Area of the column) ANSWER DOWNLOAD EXAMIANS APP
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