Theory of Structures The locus of the end point of the resultant of the normal and tangential components of the stress on an inclined plane, is Straight line Parabola Circle Ellipse Straight line Parabola Circle Ellipse ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The greatest load which a spring can carry without getting permanently distorted, is called Stiffness Proof stress Proof load Proof resilience Stiffness Proof stress Proof load Proof resilience ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A close coil helical spring of mean diameter D consists of n coils of diameter d. If it carries an axial load W, the energy stored in the spring, is 4WD²n/d4N 4W²Dn/d4N 4W²D3n/d4N 4W²D3n²/d4N 4WD²n/d4N 4W²Dn/d4N 4W²D3n/d4N 4W²D3n²/d4N ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A steel rod of sectional area 250 sq. mm connects two parallel walls 5 m apart. The nuts at the ends were tightened when the rod was heated to 100°C. If steel = 0.000012/C°, Esteel = 0.2 MN/mm², the tensile force developed at a temperature of 50°C, is 80 N/mm² 120 N/mm² 100 N/mm 2 150 N/mm² 80 N/mm² 120 N/mm² 100 N/mm 2 150 N/mm² ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The ratio of maximum shear stress to average shear stress of a circular beam, is 4/7 2/3 3/2 4/3 4/7 2/3 3/2 4/3 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures parabolic arch of span and rise , is given by The equation of a y = 4h/l² × (1 – x) y = 2h/l² × (1 – x) y = 3h/l² × (1 – x) y = h/l² × (1 – x ) y = 4h/l² × (1 – x) y = 2h/l² × (1 – x) y = 3h/l² × (1 – x) y = h/l² × (1 – x ) ANSWER DOWNLOAD EXAMIANS APP
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