Problems on H.C.F and L.C.M The least number of four digits which is divisible by 15, 25, 40 and 75 is: 9600 9000 9800 9400 9600 9000 9800 9400 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Let the leas number of six digits. which when divided by 4, 6, 10 and 15 leaves in each case the same remainder of 2 be N. The sum of the digits in N is 3 4 6 5 3 4 6 5 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number,which when divided by 48,60,72,108 and 140 leaves 38,50,62,98 and 130 as remainder respectively, is : 15120 15110 11115 15210 15120 15110 11115 15210 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the HCF of 2.1, 1.05 and 0.63 0.21 3.21 2.21 1.21 0.21 3.21 2.21 1.21 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP To solve this question quickly, first remove decimal by multiplying each term with 100,Then terms become 210, 105, 63Then HCF of above terms is 21, So Answer is 0.21
Problems on H.C.F and L.C.M The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is: 216 548 443 389 216 548 443 389 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = (L.C.M. of 12, 15, 20, 54) + 8= 540 + 8= 548.
Problems on H.C.F and L.C.M What will be the least number which when doubled will be exactly divisible by 12, 18, 21 and 30 ? 420 770 630 540 420 770 630 540 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 12, 18, 21, 30 2 | 12 - 18 - 21 - 30 ---------------------------- = 2 x 3 x 2 x 3 x 7 x 5 = 1260. 3 | 6 - 9 - 21 - 15 ---------------------------- Required number = (1260 ÷ 2) | 2 - 3 - 7 - 5 = 630.
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