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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is:

40
30
10
20

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let the numbers be 2x and 3x.Then, their L.C.M. = 6x.So, 6x = 48 or x = 8The numbers are 16 and 24.Hence, required sum = (16 + 24) = 40.

Problems on H.C.F and L.C.M
Find largest number of 4 digits divisible by 12, 15, 18, 27 ?

9720
11340
12765
10478

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

The largest 4 digit number is 9999.We know that , if LCM of given numbers divide a number N , then N is exactly divisible by all the given numbers .LCM of 12,15,18,27 is 540.On dividing 9999 by 540 we get 279 as remainder.Therefore number =9999 - 279 =9720.

Problems on H.C.F and L.C.M
Least perfect square number, exactly divisible by 21, 36 and 56 is?

7056
504
3600
441

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The wheels revolve round a common horizontal axis. They make 15, 20 and 48 revolutions in a minute respectively. Starting with a certain point on the circumference down wards. After what interval of t

3 min
None
2 min
1 min

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The largest four-digit number which when divided by 4, 7 or 13 leaves a remainder of 3 in each case,is :

9831
9834
9893
8739

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Reduce 391/667 to lowest terms .

23/37
11/13
17/29
31/45

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

H.C.F. of 391 and 667 is 23.On dividing the numerator and denominator by 23, we get :391 = 391 ¸23 = 17667    667¸ 23    29

MORE MCQ ON Problems on H.C.F and L.C.M

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