Problems on H.C.F and L.C.M The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is: 20 30 40 10 20 30 40 10 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numbers be 2x and 3x.Then, their L.C.M. = 6x.So, 6x = 48 or x = 8The numbers are 16 and 24.Hence, required sum = (16 + 24) = 40.
Problems on H.C.F and L.C.M An officer was appointed on maximum daily wages on contract money of Rs. 4956. But on being absent for some days, he was paid only Rs. 3894. For how many days was he absent? 4 5 3 6 4 5 3 6 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The smallest number which when divided by 20, 25, 35 and 40 leaves a remainder of 14, 19, 29 and 34 respectively is? 1349 1494 1496 1994 1349 1494 1496 1994 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Six belts commence tolling together and toll at intervals of 2, 4, 6, 8, 10 and 12 seconds respectively. In 30 minutes. how many times do they toll together ? 10 4 15 16 10 4 15 16 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Product of two co-prime numbers is 117. Their L.C.M should be: equal to their H. Cannot be calculated 1 F 117 equal to their H. Cannot be calculated 1 F 117 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number of five digits which is exactly divisible by 12,15 and 18 is : 10020 10010 10015 10080 10020 10010 10015 10080 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP NA
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