Problems on H.C.F and L.C.M The greatest number which can divide 1356, 1868 and 2764 leaving the same remainder 12 in each case, is: 260 124 64 156 260 124 64 156 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the L.C.M of 2/15, 3/10, 6/5 2/3 7/5 8/5 6/5 2/3 7/5 8/5 6/5 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the least number which when divided by 20,25,35 and 40 leaves remainders 14,19,29 and 34 respectively. 1194 1394 1494 1294 1194 1394 1494 1294 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Here,(20-14) = 6,(25 – 19)=6,(35-29)=6 and (40-34)=6. Required number = (L.C.M. of 20,25,35,40) – 6 =1394.
Problems on H.C.F and L.C.M An electronic device makes a beep after every 60 sec. Another device makes a beep after every 62 sec. They beeped together at 10 a.m. The time when they will next make a beep together at the earliest, 9 : 31 am 10 : 31 am 11 : 31 am 12 : 31 am 9 : 31 am 10 : 31 am 11 : 31 am 12 : 31 am ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 60 and 62 seconds is 1860 seconds1860/60 = 31 minutesThey will beep together at 10:31 a.m.Sometimes questions on red lights blinking comes in exam, which can be solved in the same way
Problems on H.C.F and L.C.M A, B and C start running around a circular stadium and complete one round in 27 s, 9 s and 36 s, respectively. In how much time will they meet again at the starting point? 3 minute 48 seconds 4 minute 48 seconds 2 minute 48 seconds 1 minute 48 seconds 3 minute 48 seconds 4 minute 48 seconds 2 minute 48 seconds 1 minute 48 seconds ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 27, 9 and 36 = 108 So they will meet again at the starting point after 108 sec. i.e., 1 min 48 sec.
Problems on H.C.F and L.C.M The least number of five digits which is exactly divisible by 12, 15 and 18, is: 10015 10080 10010 10020 10015 10080 10010 10020 ANSWER DOWNLOAD EXAMIANS APP
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