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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
Six belts commence tolling together and toll at intervals of 2, 4, 6, 8, 10 and 12 seconds respectively. In 30 minutes. how many times do they toll together ?

15
4
16
10

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The ratio of numbers is 3:4 and their H.C.F is 4. Their L.C.M is:

48
16
24
12

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Six bells commence tolling together and toll at intervals of 2, 4, 6, 8 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together ?

10
15
4
16

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

L.C.M. of 2, 4, 6, 8, 10, 12 is 120. So, the bells will toll together after every 120 seconds(2 minutes). In 30 minutes, they will toll together 30 + 1 = 16 times. 2

Problems on H.C.F and L.C.M
Let the leas number of six digits. which when divided by 4, 6, 10 and 15 leaves in each case the same remainder of 2 be N. The sum of the digits in N is

6
4
5
3

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Find the largest number of four digits exactly divisible by 12,15,18 and 27.

8720
9720
7720
6720

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

The Largest number of four digits is 9999.       Required number must be divisible by L.C.M. of 12,15,18,27 i.e. 540.      On dividing 9999 by 540,we get 279 as remainder .   Required number = (9999-279) = 9720.

Problems on H.C.F and L.C.M
Which of the following has the most number of divisors?

182
101
176
99

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Option A, 176 = 1 x 2 x 2 x 2 x 2 x 11.Option B, 182 = 1 x 2 x 7 x 13. Option C, 99 = 1 x 3 x 3 x 11. Option D, 101 = 1 x 101.Divisors of 99 are 1, 3, 9, 11, 33, 99.Divisors of 176 are 1, 2, 4, 8, 11, 16, 22, 44, 88 and 176. Divisors of 182 are 1, 2, 7, 13, 14, 26, 91 and 182.Hence, 176 have the most number of divisors.

MORE MCQ ON Problems on H.C.F and L.C.M

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