The D-slide valve is also known as Inside admission valve None of these Outside admission valve Piston slide valve TRUE ANSWER : ? YOUR ANSWER : ?
In a cone pulley, if the sum of radii of the pulleys on the driving and driven shafts is constant, then The drive is recommended depending upon the torque transmitted Crossed belt drive is recommended Both open belt drive and crossed belt drive is recommended Open belt drive is recommended TRUE ANSWER : ? YOUR ANSWER : ?
A torsional system with discs of moment of inertia I₁ and I₂ as shown in the below figure, is gear driven such that the ratio of speed of shaft B to shaft A is 'G'. Neglecting the inertia of gears, the equivalent inertia of disc on shaft B at the speed of shaft A is equal to G.I₂ G².I₂ I₂/G² I₂/G TRUE ANSWER : ? YOUR ANSWER : ?
The secondary unbalanced force due to inertia of reciprocating parts in a reciprocating engine is given by (where m = Mass of reciprocating parts, ω = Angular speed of crank, r = Radius of crank, θ = Angle of inclination of crank with the line of stroke, and n = Ratio of the length of connecting rod to radius of crank) m.ω².r (sin 2θ/n) m.ω².r cosθ m.ω².r sinθ m.ω².r (cos 2θ/n) TRUE ANSWER : ? YOUR ANSWER : ?
When the axes of the first and last wheels are coaxial, then the train is known as Simple train of wheels Epicyclic gear train Reverted gear train Compound train of wheels TRUE ANSWER : ? YOUR ANSWER : ?
The effort of a Porter governor is equal to (where c = Percentage increase in speed, m = Mass of ball, and M = Mass on the sleeve) c/(m - M) g c (m + M) g c (m - M) g c/(m + M) g TRUE ANSWER : ? YOUR ANSWER : ?
The swaying couple is due to the Secondary unbalanced force Primary unbalanced force Two cylinders of locomotive Partial balancing TRUE ANSWER : ? YOUR ANSWER : ?
The frictional torque transmitted in a truncated conical pivot bearing, considering uniform wear, is (1/2). μ W cosec α (r₁ + r₂) (2/3). μ W cosec α [(r₁³ - r₂³)/(r₁² - r₂²)] (2/3).μ W cosec α (r₁ + r₂) (1/2). μ W cosec α [(r₁³ - r₂³)/(r₁² - r₂²)] TRUE ANSWER : ? YOUR ANSWER : ?
The secondary unbalanced force due to inertia of reciprocating parts in a reciprocating engine is given by (where m = Mass of reciprocating parts, ω = Angular speed of crank, r = Radius of crank, θ = Angle of inclination of crank with the line of stroke, and n = Ratio of the length of connecting rod to radius of crank) m.ω².r cosθ m.ω².r (cos 2θ/n) m.ω².r (sin 2θ/n) m.ω².r sinθ TRUE ANSWER : ? YOUR ANSWER : ?
For S.H.M. cam, the acceleration of the follower at the ends of the stroke and aimed stroke respectively, is Zero and minimum Minimum and maximum Maximum and zero Zero and maximum TRUE ANSWER : ? YOUR ANSWER : ?