A 1.2 kΩ resistor is in series with a 15 mH coil across a 10 kHz ac source. The magnitude of the total impedance is 1526Ω 152.6Ω 1200Ω 942Ω TRUE ANSWER : ? YOUR ANSWER : ?
A 47Ω resistor is in series with an inductive reactance of 120Ω across an ac source. The impedance, expressed in polar form, is 120 angle 68.6° 129 angle 31.4° 129 angle 68.6° 47 angle 68.6° TRUE ANSWER : ? YOUR ANSWER : ?
A 470Ω resistor and a 200 mH coil are in parallel. Both components are across a 1.5 kHz ac source. The total admittance of the circuit, in polar form, is 12.60 angle –76° mS 12.18 angle –76° mS 218 angle –76° mS 12.18 angle 76° mS TRUE ANSWER : ? YOUR ANSWER : ?
A 470Ω resistor and a coil with 125Ω inductive reactance are in parallel. Both components are across a 15 V ac voltage source. Current through the inductor is 32 mA 12 mA 120 mA 152 mA TRUE ANSWER : ? YOUR ANSWER : ?
In a series RL circuit, 12 V rms is measured across the resistor, and 14 V rms is measured across the inductor. The peak value of the source voltage is 20 V 26.0 V 18.4 V 2 V TRUE ANSWER : ? YOUR ANSWER : ?
A 3.3 kΩ resistor and a 120 mH coil are in parallel. Both components are across a 2 kHz, 12 V ac source. The total current in the circuit is 874 mA 8.74 mA 874 A 8.74 A TRUE ANSWER : ? YOUR ANSWER : ?
To increase the current in a series RL circuit, the frequency should be constant should be decreased cannot be determined without values should be increased TRUE ANSWER : ? YOUR ANSWER : ?
When the frequency is decreased, the impedance of a parallel RL circuit remains constant decreases is not a factor increases TRUE ANSWER : ? YOUR ANSWER : ?
A 12 kΩ resistor is in series with a 90 mH coil across an 8 kHz ac source. Current flow in the circuit, expressed in polar form, is I = 0.3 angle 0° mA. The source voltage, expressed in polar form, is 12.8 angle 20.6° V 0.3 angle 20.6° V 13.84 angle 69.4° V 3.84 angle 20.6° V TRUE ANSWER : ? YOUR ANSWER : ?
When the frequency of the voltage applied to a series RL circuit is decreased, the impedance cannot be determined without values decreases does not change increases TRUE ANSWER : ? YOUR ANSWER : ?