The bank of tubes at the back of domestic refrigerator is Refrigerant cooling tubes Capillary tubes Condenser tubes Evaporator tubes TRUE ANSWER : ? YOUR ANSWER : ?
The wet bulb temperature at 100% relative humidity is ________ dew point temperature. Lower than Higher than None of these Same as TRUE ANSWER : ? YOUR ANSWER : ?
One ton refrigeration corresponds to 80 kcal/ hr 80 kcal/ min 50 kcal/ min 50 kcal/ hr TRUE ANSWER : ? YOUR ANSWER : ?
Dry bulb temperature is the temperature of air recorded by a thermometer, when Its bulb is surrounded by a wet cloth exposed to the air The moisture present in it begins to condense It is not affected by the moisture present in the air None of the listed here TRUE ANSWER : ? YOUR ANSWER : ?
In a vapour compression cycle, the refrigerant immediately after expansion valve is Sub-cooled liquid Liquid Saturated liquid Wet vapour TRUE ANSWER : ? YOUR ANSWER : ?
An important characteristic of absorption system of refrigeration is very little power consumption noisy operation quiet operation cooling below 0°C TRUE ANSWER : ? YOUR ANSWER : ?
The bypass factor (B. P. F.) in case of sensible heating of air is (Where td₁ = Dry bulb temperature of air entering the heating coil, td₂ = Dry bulb temperature of air leaving the heating coil, and td₃ = Dry bulb temperature of heating coil) (td₃ - td₁)/(td₃ - td₂) (td₂ - td₃)/(td₃ - td₁) (td₃ - td₂)/(td₃ - td₁) (td₃ - td₁)/(td₂ - td₃) TRUE ANSWER : ? YOUR ANSWER : ?
The alignment circle is marked on the psychrometric chart at 20°C DBT and 50% RH 20°C DBT and 60% RH 26°C DBT and 60% RH 26°C DBT and 50% RH TRUE ANSWER : ? YOUR ANSWER : ?
During sensible heating of air _________ decreases. Relative humidity Specific humidity Wet bulb temperature Dry bulb temperature TRUE ANSWER : ? YOUR ANSWER : ?
A refrigerating system operating on reversed Brayton refrigeration cycle is used for maintaining 250 K. If the temperature at the end of constant pressure cooling is 300 K and rise in the temperature of air in the refrigerator is 50 K, then the net work of compression will be (assume air as working substance with Cp = 1 kJ/kg) 125 kJ/kg 100 kJ/kg 25 kJ/kg 50 kJ/kg TRUE ANSWER : ? YOUR ANSWER : ?