By over-reinforcing a beam, the moment of resistance can be increased not more than 15 % 20 % 25 % 10 % TRUE ANSWER : ? YOUR ANSWER : ?
A flat slab is supported On beams On columns monolithically built with slab On beams and columns On columns TRUE ANSWER : ? YOUR ANSWER : ?
The width of the flange of a L-beam, should be less than One-sixth of the effective span Least of the above Breadth of the rib + four times thickness of the slab Breadth of the rib + half clear distance between ribs TRUE ANSWER : ? YOUR ANSWER : ?
In a combined footing for two columns carrying unequal loads, the maximum hogging bending moment occurs at Less loaded column A point of zero shear force More loaded column A point of the maximum shear force TRUE ANSWER : ? YOUR ANSWER : ?
In favourable circumstances a 15 cm concrete cube after 28 days, attains a maximum crushing strength 400 kg/cm² 300 kg/cm² 200 kg/cm² 100 kg/cm² TRUE ANSWER : ? YOUR ANSWER : ?
An under-reinforced section means Steel provided is insufficient Steel provided on one face only Steel is provided at the underside only Steel will yield first TRUE ANSWER : ? YOUR ANSWER : ?
After pre-stressing process is completed, a loss of stress is due to All of the listed here Elastic shortening of concrete Shrinkage of concrete Creep of concrete TRUE ANSWER : ? YOUR ANSWER : ?
The shear reinforcement in R.C.C. is provided to resist Vertical shear Diagonal tension Horizontal shear Diagonal compression TRUE ANSWER : ? YOUR ANSWER : ?
A simply supported beam 6 m long and of effective depth 50 cm, carries a uniformly distributed load 2400 kg/m including its self weight. If the lever arm factor is 0.85 and permissible tensile stress of steel is 1400 kg/cm², the area of steel required, is 17 cm² 16 cm² 15 cm² 14 cm² TRUE ANSWER : ? YOUR ANSWER : ?
If q is the punching shear resistance per unit area a, is the side of a square footing for a column of side b, carrying a weight W including the weight of the footing, the depth (D) of the footing from punching shear consideration, is D = W (a - b)/4a²bq D = W (a² - b²)/4a²bq D = W (a² - b²)/4abq D = W (a² - b²)/8a²bq TRUE ANSWER : ? YOUR ANSWER : ?