DECLARATION AND ACCESS CONTROL QUIZ

What will be the output for the below code?public class Test{ static{ int a = 5; } public static void main(String[] args){ System.out.println(a); }}

Compile with error

5

Runtime Exception

0

None of these

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Suppose a class has public visibility. In this class we define a protected method. Which of the following statements is correct?

This method is only accessible from inside the class itself and from inside all subclasses.

This method is accessible from within the class itself and from within all classes defined in the same package as the class itself.

From within protected methods you do not have access to public methods.

In a class, you cannot declare methods with a lower visibility than the visibility of the class in which it is defined.

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Determine Output:class MyClass{ static final int a = 20; static final void call(){ System.out.println("two"); } static{ System.out.println("one"); }}public class Test{ public static void main(String args[]){ System.out.println(MyClass.a); }}

one 20

20

one two 20

one two

one

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What is the result of compiling and running the following code?public class Tester{static int x = 4;public Tester(){System.out.print(this.x); // line 1Tester();}public static void Tester(){ // line 2System.out.print(this.x); // line 3}public static void main(String... args){ // line 4new Tester();}}

Compile error at line 2 (constructors can't be static)

44

Compile error at line 4 (invalid argument type for method main )

Compile error at line 3 (static methods can't invoke this)

Compile error at line 1 (static x must be only accessed inside static methods)

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What will be the output after the following program is compiled and executed?public class Test{ public static void main(String args[]){ int x = 10; x = myMethod(x--); System.out.print(x); } static int myMethod(final int x){ return x--; }}

The program will lead to compilation error.

The will compile successfully and display 9 as output.

The program will lead to runtime error.

None of these

The program will compile successfully and display 10 as output.

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A method within a class is only accessible by classes that are defined within the same package as the class of the method. Which one of the following is used to enforce such restriction?

Declare the method with the keyword protected.

Declare the method with the keyword private.

Declare the method with the keyword public.

Do not declare the method with any accessibility modifiers.

Declare the method with the keyword public and private.

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Choose the correct statementpublic class Circle{ private double radius; public Circle(double radius){ radius = radius; }}

The program will compile, but we cannot create an object of Circle with a specified radius. The object will always have radius 0.

The program does not compile because Circle does not have a default constructor.

The program has a compilation error because we cannot assign radius to radius.

The program has a compilation error because it does not have a main method.

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Choose all the lines which if inserted independently instead of "//insert code here" will allow the following code to compile:public class Test{ public static void main(String args[]){ add(); add(1);add(1, 2); }// insert code here}

static void add(int... args, int y){}

void add(Integer... args){}

static void add(int args...){}

static void add(int[]... args){}

static void add(int...args){}

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A package is a collection of

Editing tools and Interfaces

Interfaces

Classes

Editing tools

Classes and Interfaces

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What will be the output for the below code?static public class Test{ public static void main(String[] args){ char c = 'a'; switch(c){ case 65 : System.out.println("one");break; case 'a': System.out.println("two");break; case 3 : System.out.println("three"); } }}

Compile error - char can't be permitted in switch statement.

one

two

Compile error - Illegal modifier for the class Test; only public, abstract & final are permitted.

None of these

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