A body of weight 14 g appears to weight 13 g when weighed by a spring balance in a moving lift. The acceleration of the lift at that moment was 0.7 m/sec² 1 m/sec² 0.5 m/sec² 1 cm/sec² TRUE ANSWER : ? YOUR ANSWER : ?
The Law of Polygon of Forces states that If forces acting on a point can be represented in magnitude and direction by the sides of a polygon taken in order, then the resultant of the forces will be represented in magnitude and direction by t If a polygon representing the forces acting at point in a body is closed, the forces are in equilibrium If forces acting on a point can be represented in magnitude and direction by the sides of a polygon in order, the forces are in equilibrium If forces acting on a point can be represented of a polygon taken in order, their sides of a polygon taken in order, their resultant will be represented in magnitude and direction by the closing side TRUE ANSWER : ? YOUR ANSWER : ?
The product of mass and velocity of a moving a body, is called Power Impulse Moment Momentum TRUE ANSWER : ? YOUR ANSWER : ?
The numbers of funicular polygons which can be drawn to pass through two specified points in the space diagram are 2 Zero Infinity 1 TRUE ANSWER : ? YOUR ANSWER : ?
The member which does not carry zero force in the structure shown in below figure, is BC DC BD ED TRUE ANSWER : ? YOUR ANSWER : ?
The velocity of a body fallen from height ‘h’, on reaching the ground is given by v = 1/√(2gh) v = 2gh v = 2gh² v = √(2gh) TRUE ANSWER : ? YOUR ANSWER : ?
A load of 500 kg was lifted through a distance of 13 cm. by an effort of 25 kg which moved through a distance of 650 cm. The mechanical advantage of the lifting machine is 26 18 20 15 TRUE ANSWER : ? YOUR ANSWER : ?
A weight of 100 kg is supported by a string whose ends are attached to pegs ‘A’ and ‘B’ at the same level shown in below figure. The tension in the string is Applied Mechanics and Graphic Statics mcq question image 120 kg 130 kg 100 kg 150 kg TRUE ANSWER : ? YOUR ANSWER : ?
If the resultant of two forces ‘P’ and ‘Q’ acting at an angle ‘θ’ makes an angle ‘α’ with ‘P’, then tan α equals Q sin θ/P + Q sin θ P sin θ/P - Q cos θ P sin θ/P + Q tan θ Q sin θ/P + Q cos θ TRUE ANSWER : ? YOUR ANSWER : ?