RCC Structures Design ‘P’ is the pre-stressed force applied to tendon of a rectangular pre-stressed beam whose area of cross section is ‘A’ and sectional modulus is ‘Z’. The minimum stress ‘f’ on the beam subjected to a maximum bending moment ‘M’ is f = (P/A) - (M/6Z) f = (P/A) - (M/Z) f = (A/P) - (M/Z) f = (P/'- (Z/M) f = (P/A) - (M/6Z) f = (P/A) - (M/Z) f = (A/P) - (M/Z) f = (P/'- (Z/M) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A simply supported beam 6 m long and of effective depth 50 cm, carries a uniformly distributed load 2400 kg/m including its self weight. If the lever arm factor is 0.85 and permissible tensile stress of steel is 1400 kg/cm², the area of steel required, is 16 cm² 17 cm² 15 cm² 14 cm² 16 cm² 17 cm² 15 cm² 14 cm² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Side face reinforcement shall be provided in the beam when depth of the web in a beam exceeds 100 cm 75 cm 50 cm 120 cm 100 cm 75 cm 50 cm 120 cm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The maximum shear stress (q) in concrete of a reinforced cement concrete beam is Lever arm/(Shear force × Width) Width/(Lever arm × Shear force) Shear force/(Lever arm × Width) (Shear force × Width)/Lever arm Lever arm/(Shear force × Width) Width/(Lever arm × Shear force) Shear force/(Lever arm × Width) (Shear force × Width)/Lever arm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The diameter of the column head support a flat slab, is generally kept 0.25 times the span length 4.0 cm larger than the diameter of the column 0.25 times the diameter of the column 5.0 cm larger than the diameter of the column 0.25 times the span length 4.0 cm larger than the diameter of the column 0.25 times the diameter of the column 5.0 cm larger than the diameter of the column ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The transverse reinforcements provided at right angles to the main reinforcement All of these Resist the temperature stresses Distribute the load Resist the shrinkage stress All of these Resist the temperature stresses Distribute the load Resist the shrinkage stress ANSWER DOWNLOAD EXAMIANS APP
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