Problems on H.C.F and L.C.M LCM of 87 and 145 is: 1305 875 435 48 1305 875 435 48 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M What is the least number of that is exactly divisible by 4, 12, 15, and 18? 150 60 110 180 150 60 110 180 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of (4, 12, 15, and 18) 2|4 12 15 18 3|2 6 15 9 2|2 2 5 3 1 1 5 3 Least number which is exactly divisible by 4,12,15 and 18 is =180
Problems on H.C.F and L.C.M 1095/1168 when expressed in simplest form is: 17/26 25/26 15/16 13/16 17/26 25/26 15/16 13/16 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M In a school, the number of students in Sections A , B and C of 10th class are 70,98 and 126 respectively. Due to overload of student in each class , the administration wants to increase the number roo 17 21 14 28 17 21 14 28 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The number students in each room = HCF of 70,98 and 126 =14 In each room , maximum 14 students can be seated. Total number students = 70 + 98 +126 =294 Number of rooms required = 294/14 =21
Problems on H.C.F and L.C.M A. B. and C. start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and C in 198 seconds.all starting at the same point. 42 minutes 36 seconds 26 minutes 18 seconds 45 minutes 46 minutes 12 seconds. 42 minutes 36 seconds 26 minutes 18 seconds 45 minutes 46 minutes 12 seconds. ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M 252 can be expressed as a product of primes as: 2 x 2 x 2 x 3 x 7 2 x 2 x 3 x 3 x 7 2 x 3 x 3 x 3 x 7 3 x 3 x 3 x 3 x 7 2 x 2 x 2 x 3 x 7 2 x 2 x 3 x 3 x 7 2 x 3 x 3 x 3 x 7 3 x 3 x 3 x 3 x 7 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Clearly, 252 = 2 x 2 x 3 x 3 x 7.
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