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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
LCM of 87 and 145 is:

1305
435
875
48

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Six bells commence tolling together and toll at the intervals of 2,4,6,8,10,12 seconds resp. In 60 minutes how many times they will toll together.

24
21
31
17

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

LCM of 2-4-6-8-10-12 is 120 seconds, that is 2 minutes.Now 60/2 = 30Adding one bell at the starting it will 30+1 = 31

Problems on H.C.F and L.C.M
Find the least which when divided y 16,18,20, and 25 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder.

17004
18000
18002
18004

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
What is the least number when divided by 4, 5, 6, 8 and 10 leaves 3 as remainder?

116
112
123
121

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

 The least number which when divided by 4,5,6,8 and 10 is the LCM of these numbers. But each time  to get 3 as remainder, we have to add the remainder 3 to the obtained LCM.LCM of (4, 5, 6, 8, 10)+ 3=120+3=123

Problems on H.C.F and L.C.M
A. B. and C. start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and C in 198 seconds.all starting at the same point.

42 minutes 36 seconds
46 minutes 12 seconds.
26 minutes 18 seconds
45 minutes

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
Product of two co-prime numbers is 117. Their L.C.M should be:

Cannot be calculated
F
117
equal to their H.
1

ANSWER DOWNLOAD EXAMIANS APP
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