L.C.M. of 5, 6, 7, 8 = 840.Required number is of the form 840k + 3Least value of k for which (840k + 3) is divisible by 9 is k = 2.Required number = (840 x 2 + 3) = 1683.
Converting given measurements into centimeters 4m 96 cm = 400+96 = 496 cm 4m 3cm = 400+3 =403 cmTo find the side of the largest possible brick , the side of brick must divide length as well as breadth exactly. Using division method 403)496(1 403 93) 403 (4 370 31) 93 (3 93 0HCF = 31 Side of the largest possible square brick =31cm
L.C.M. of 60 and 62 seconds is 1860 seconds1860/60 = 31 minutesThey will beep together at 10:31 a.m.Sometimes questions on red lights blinking comes in exam, which can be solved in the same way
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