Problems on H.C.F and L.C.M Find the HCF of 54, 288, 360 16 19 18 17 16 19 18 17 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Lets solve this question by factorization method.18=2×3²,288=2×2×2×2×2×3²,360=2³×3²×5So HCF will be minimum term present in all three, i.e.2×3²=18
Problems on H.C.F and L.C.M A, B and C start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and c in 198 seconds, all starting at the same point. Aft 46 minutes and 12 seconds 45 minutes 26 minutes and 18 seconds 42 minutes and 36 seconds 46 minutes and 12 seconds 45 minutes 26 minutes and 18 seconds 42 minutes and 36 seconds ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 252, 308 and 198 = 2772.So, A, B and C will again meet at the starting point in 2772 sec. i.e., 46 min. 12 sec.
Problems on H.C.F and L.C.M Find the largest number of four digits which is exactly divisible by 27,18,12,15 8720 10720 9720 11720 8720 10720 9720 11720 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 27-18-12-15 is 540.After dividing 9999 by 540 we get 279 remainder.So answer will be 9999-279 = 9720
Problems on H.C.F and L.C.M Reduce 4128/4386 to its lowest terms 13/18 14/13 16/17 13/17 13/18 14/13 16/17 13/17 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The maximum number of students among them 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is: 1001 91 1911 910 1001 91 1911 910 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Which greatest possible length can be used to measure exactly 15 meter 75 cm, 11 meter 25 cm and 7 meter 65 cm 275 cm 285 cm 265 cm 255 cm 275 cm 285 cm 265 cm 255 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Convert first all terms into cm.i.e. 1575 cm, 1125cm, 765cm.Now whenever we need to calculate this type of question, we need to find the HCF.HCF of above terms is 255.
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