MGVCL Exam Paper (30-07-2021 Shift 1) In computer networks, the nodes are the computer that terminates data all the mentioned above the computer that originates data the computer that routes data the computer that terminates data all the mentioned above the computer that originates data the computer that routes data ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) In Microsoft Word, which of the following menu is used to add Headings that are displayed automatically in the top margin of all pages? Insert Menu Format Menu View Menu Tools Menu Insert Menu Format Menu View Menu Tools Menu ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) મારુતારુંનો ઝગડો હજી ખતમ થયો નથી, ચારપાંચ વર્ષ થઇ ગયા અને રાતદિવસ સાથે ઉઠવા-બેસવાનું તો ચાલુ જ છે. ઉપરોક્ત વાક્યમાં ક્યા ક્યા વ્યાકરણીય સમાસનો ઉપયોગ કરાયો છે? અવ્યવીભાવ, મધ્યમપદલોપી દ્વન્દ્વ, મધ્યમપદલોપી દ્વન્દ્વ તત્પુરુષ, અવ્યવીભાવ, મધ્યમપદલોપી દ્વન્દ્વ, મધ્યમપદલોપી દ્વન્દ્વ તત્પુરુષ, ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) At what range of wind speed is the electricity from the wind turbine is generated? 450 – 650 mph 30-35 mph 250 – 450 mph 100 – 125 mph 450 – 650 mph 30-35 mph 250 – 450 mph 100 – 125 mph ANSWER EXPLANATION DOWNLOAD EXAMIANS APP For small turbine starts generating power 12.6 kph (3.5 m/s) is the typical cut-in speed.At 36–54 kph (10–15 m/s) produces maximum generation power.At 90 kph (25 m/s) maximum, the turbine is stopped or braked.
MGVCL Exam Paper (30-07-2021 Shift 1) A given solar cell has the following specifications:Open-circuit voltage, Voc: 0.7 VShort-circuit current, Isc: 3.5 AShort-circuit current, Isc: 3.5 AShort-circuit current, Isc: 3.5 AIf the solar cell operates at maximum power point, calculate the efficiency. 15.70% 12.70% 14.70% 13.70% 15.70% 12.70% 14.70% 13.70% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Equation is given by:Efficiency = (F.F*Voc*Isc)/Pin= (0.6*3.5*0.7)/10= 0.14702% efficiency = 14.7 %
MGVCL Exam Paper (30-07-2021 Shift 1) Three resistances 750 Ω, 600 Ω and 200 Ω are connected in parallel. The total current is 1 A. Determine the voltage applied. 125 V 100 V 150 V 200 V 125 V 100 V 150 V 200 V ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Equivalent resistance of the circuit, Req = (750|| 600 || 200)Req = 125 ΩCurrent from source = 1 ASource voltage = 1*125Source voltage = 125 V
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