Area Problems if the side of a square be increased by 4 cms. The area increased by 60 sq. cms . The side of the square is? 12 cm None of these 13 cm 14cm 12 cm None of these 13 cm 14cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let each side = x cmThen, (x + 4 )2 - x2 = 60? x 2 + 8x + 16 - x2 = 60? x = 5.5 cm
Area Problems The two parallel sides of a trapezium are 1 meters and 2 meters respectively . The perpendicular distance between them is 6 meters. The area of the trapezium is? 12 sq. meters . 9 sq. meters . 18 sq. meters . 6 sq. meters . 12 sq. meters . 9 sq. meters . 18 sq. meters . 6 sq. meters . ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of trapezium = 1/2 x sum of parallel sides x perpendicular distance between them= 1/2 (1 + 2) x 6 m2= 9 m2
Area Problems A man runs round a circular field of radius 50m at the speed of 12 km/hr. What is the time taken by the man to take twenty rounds of the field? 230/7 min 90/7 min 220/7 min 110/7 min 230/7 min 90/7 min 220/7 min 110/7 min ANSWER EXPLANATION DOWNLOAD EXAMIANS APP speed = 12 km/h = 12 × 5 18 = 10 3 m / s distance covered = 20 × 2 × 22 7 × 50 = 44000 7 m time taken = distance /speed = 44000 7 × 3 10 s e c = 4400 × 3 7 × 1 60 m i n = 220 7 m i n
Area Problems A circular disc of area 0.49 ? square meters, rolls down a length of 1.76 km. The number of revolutions it makes is? 300 4000 600 400 300 4000 600 400 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area = ?r2 = 0.49? ? r = 0.7 mNumber of revolutions = total distance / circumference = (1.76 x 1000) / (2 x 22/7 x 0.7) = 400
Area Problems If a regular hexagon is inscribed in a circle of radius, r then its perimeter? 9r 3r 12r 6r 9r 3r 12r 6r ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Length of each side of hexagoan = radius of circle ? its perimeter = 6r
Area Problems If the sides of a rectangle are increased by 10% find the percentage increased in its diagonals. 15% 20% 10% 18% 15% 20% 10% 18% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP According to the formula,? Percentage increase in sides = 10%? Percentage increase diagonals = 10%
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