Area Problems if the side of a square be increased by 4 cms. The area increased by 60 sq. cms . The side of the square is? 14cm 12 cm 13 cm None of these 14cm 12 cm 13 cm None of these ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let each side = x cmThen, (x + 4 )2 - x2 = 60? x 2 + 8x + 16 - x2 = 60? x = 5.5 cm
Area Problems A circle and a square have same area. The ratio of the side of the square and the radius of the circle is? 1 : ? 1 : ?? ? : 1 ?? : 1 1 : ? 1 : ?? ? : 1 ?? : 1 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP ? Area of square = Area of circle ? x2 = ?r2? x/r = ?? = ? ? : 1
Area Problems In a circle of radius 21 cm an arc subtends an angle of 72° at the centre. The length of the arc is? 19.8 cm 13.2 cm 21.6 cm 26.4 cm 19.8 cm 13.2 cm 21.6 cm 26.4 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Arc length = 2?r (?° / 360°) = 2 x (22/7) x 21 x (72° / 360°) cm= 26.4 cm
Area Problems The area of a trapezium is 384 sq.cm. If its parallel sides in ratio 3 : 5 and the perpendicular distance between them be 12 cm. The smaller of parallel sides is? 16 cm 24 cm 40 cm 32 cm 16 cm 24 cm 40 cm 32 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the parallel sides be 3a and 5a.So Area of trapezium = 1/2 x sum of parallel side x perpendicular distance between them.? 1/2 (3a +5a) x 12 = 384? 8a = 64? a =8? Smaller side = 3x = 3 x 8 = 24 cm.
Area Problems The length of a rectangle is double while its breadth is halved. What is the percentage change in area? No change 50 None of these 75 No change 50 None of these 75 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let length = l and breadth = bThen, area = lb New length = 2lAnd new breadth = b/2 ? New area = ( 2l ) x (b/2) = lbSo, there is no change in area .
Area Problems The ratio of the area of the circumcircle and the incircle of a square is 1 : 2 ?2 : 1 2 : 1 1 : ?2 1 : 2 ?2 : 1 2 : 1 1 : ?2 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Ratio of the areas of the circumcircle and incircle of a square = [(Diagonal)2?] / [(Side)2?]= [(Side x ?2)2] / (Side)2 = 2/1 or 2 : 1
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