Area Problems if the side of a square be increased by 4 cms. The area increased by 60 sq. cms . The side of the square is? None of these 14cm 13 cm 12 cm None of these 14cm 13 cm 12 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let each side = x cmThen, (x + 4 )2 - x2 = 60? x 2 + 8x + 16 - x2 = 60? x = 5.5 cm
Area Problems The sides of a triangular board are 13 meters, 14 meters and 15 meters. The cost of paining it at the rate of Rs. 8.75 per m 2 is? Rs. 730.80 Rs. 735 Rs. 722.50 Rs. 688.80 Rs. 730.80 Rs. 735 Rs. 722.50 Rs. 688.80 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP s = (13 + 14 + 15 ) / 2 = 21, s-a = 8 , s-b = 7, s-c= 6? Area to be painted = ? [s(s-a) (s-b) (s-c)]=? [21 x 8 x 7 x 6] m2= 84 m2? Cost of painting = Rs. (84 x 8.75) = Rs. 735
Area Problems The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ 26.50 per metre is Rs. 5300, what is the length of the plot in metres? None of these 40 120 Data inadequate None of these 40 120 Data inadequate ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let breadth = x metres. Then, length = (x + 20) metres. Perimeter = ❨ 5300 ❩ m = 200 m. 26.50 ∴ 2[(x + 20) + x] = 200 ⟹ 2x + 20 = 100 ⟹ 2x = 80 ⟹ x = 40. Hence, length = x + 20 = 60 m
Area Problems The cost of carpeting a room 15 meters long with a carpet 75 cm wide at 30 paisa per meter is Rs. 36. The breadth of the room is? 9 meters 6 meters 8 meters 12 meters 9 meters 6 meters 8 meters 12 meters ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Length of carpet = Total Cost / Rate = 3600 / 30 = 120 mArea of carpet = (120 x 75) / 100 m2= 90 m2? Area of the room = 90 m2Breadth of the room = Area /Length = 90 / 15 m = 6m
Area Problems Find the area of a rectangle having 15m length and 8m breadth. 120 sq m 125 sq m 115 sq m 111 sq m 120 sq m 125 sq m 115 sq m 111 sq m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required area = Length x Breadth= 15 x 8 = 120 sq m
Area Problems A wheel make 4000 revolution in moving a distance of 44 km. Find the radius of the wheel. 1.75 m 27 m 25 m 28 m 1.75 m 27 m 25 m 28 m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Distance covered in 1 revolution = (44 x 1000) / 4000 = 11 mAccording to the question, 2?r = 11 ? (44/7) x r = 11? r = (11 x 7) / 44 = 1.75 m
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