RCC Structures Design If the modular ratio is ‘m’, steel ratio is ‘r’ and overall depth of a beam is ‘d’, the depth of the critical neutral axis of the beam, is [m/(m + r)] d [(m + r)/m] d [m/(m - r)] d [(r - m)/m] d [m/(m + r)] d [(m + r)/m] d [m/(m - r)] d [(r - m)/m] d ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a doubly-reinforced beam if ‘c’ and ‘t’ are stresses in concrete and tension reinforcement, ‘d’ is the effective depth and ‘n’ is depth of critical neutral axis, the following relationship holds good (t + c)/n = (d + n)/n (m + c)/t = n/(d + n) mc/t = (d - n)/t mc/t = n/(d - n) (t + c)/n = (d + n)/n (m + c)/t = n/(d + n) mc/t = (d - n)/t mc/t = n/(d - n) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design ‘P’ is the pre-stressed force applied to the tendon of a rectangular pre-stressed beam whose area of cross section is ‘A’ and sectional modulus is ‘Z’. The maximum stress ‘f’ in the beam, subjected to a maximum bending moment ‘M’, is f = (P/A) + (M/Z) f = (A/P) + (M/Z) f = (P/A) + (M/6Z) f = (P/'+ (Z/M) f = (P/A) + (M/Z) f = (A/P) + (M/Z) f = (P/A) + (M/6Z) f = (P/'+ (Z/M) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If L is the effective span of a R.C.C. beam which is subjected to maximum shear qmax at the ends, the distance from either end over which stirrups for the shear, are provided, is (L/2) (1 - 2/qmax) (L/2) (1 - 3/qmax) (L/2) (1 - 5/qmax) (L/3) (1 - 5/qmax) (L/2) (1 - 2/qmax) (L/2) (1 - 3/qmax) (L/2) (1 - 5/qmax) (L/3) (1 - 5/qmax) ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a singly reinforced beam, if the permissible stress in concrete reaches earlier than that in steel, the beam section is called Over reinforced section Critical section Under-reinforced section Economic section Over reinforced section Critical section Under-reinforced section Economic section ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If p1 is the vertical intensity of pressure at a depth h on a block of earth weighing w per unit volume and the angle of repose φ, the lateral intensity of pressure p2 is wh (1 - tan φ)/(1 + tan φ) wh (1 - sin φ)/(1 + sin φ) wh (1 - cos φ)/(1 + sin φ) w (1 - cos φ)/h (1 + sin φ) wh (1 - tan φ)/(1 + tan φ) wh (1 - sin φ)/(1 + sin φ) wh (1 - cos φ)/(1 + sin φ) w (1 - cos φ)/h (1 + sin φ) ANSWER DOWNLOAD EXAMIANS APP
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