Area Problems If the diagonal of a square is double, how does the area of the square change? None of these Becomes two fold Becomes three fold Becomes four fold None of these Becomes two fold Becomes three fold Becomes four fold ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Ratio of the areas = area of original square / area of new square = [ d2 / 2 ] / [ (2d)2 / 2 ] = 1/4? New area becomes 4 fold.
Area Problems If the sides of a rectangle are increased by 10% find the percentage increased in its diagonals. 10% 18% 15% 20% 10% 18% 15% 20% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP According to the formula,? Percentage increase in sides = 10%? Percentage increase diagonals = 10%
Area Problems The difference between the circumference and the radius of a circle is 37 cm. The area of a circle is? 111 sq. cm 154 sq. cm 259 sq. cm 148 sq. cm 111 sq. cm 154 sq. cm 259 sq. cm 148 sq. cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP ? 2?r - r = 37? [(2 x 22/7) -1]r= 37? 37r / 7= 37? r = 7 So, area of the circle =(22/7) x 7 x 7 cm2= 154 cm2
Area Problems What is the area of a square having perimeter 68 cm? 289 sq cm 284 sq cm 269 sq cm 361 sq cm 289 sq cm 284 sq cm 269 sq cm 361 sq cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP According to the question,4a = 68 [ where a = side]?a = 68/4 = 17 cm? Required area = a2= (17)2 = 289 sq cm
Area Problems If the radius of a circle be reduced by 50%. Its area is reduced by? 65.5% 39.5% 31.5% 34.5% 65.5% 39.5% 31.5% 34.5% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Original area = ? x (r/2)2 = ?r2/4Reduction in area = ? r2 - 3? r2/4? Reduction per cent = [ 3?r2/4 x 4/(?r2) x 100 ] %= 75%
Area Problems A railing of 288 m is required for fencing a semi-circular park. Find the area of the park. (? = 22/7) 8956 m2 4928 m2 9865 m2 9856 m2 8956 m2 4928 m2 9865 m2 9856 m2 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the radius of the park be r, then?r + 2r = 288(? + 2)r = 288? [(22/7) + 2]r = 288? r = (288 x 7)/36 = 56 ? Area of the park = (1/2)?r2= (1/2) x (22/7) x 56 x 56= 4928
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