Engineering Mechanics If tension in the cable supporting a lift moving downwards is half the tension when it is moving upwards, the acceleration of the lift is g/4 g/3 None of these g/2 g/4 g/3 None of these g/2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The loss of kinetic energy during inelastic impact, is given by (where m1 = Mass of the first body,m2 = Mass of the second body, and u1 and u2 = Velocities of the first and second bodies respectively.) [m₁ m₂/2(m₁ + m₂)] (u₁² - u₂²) [2(m₁ + m₂)/m₁ m₂] (u₁ - u₂)² [2(m₁ + m₂)/m₁ m₂] (u₁² - u₂²) [m₁ m₂/2(m₁ + m₂)] (u₁ - u₂)² [m₁ m₂/2(m₁ + m₂)] (u₁² - u₂²) [2(m₁ + m₂)/m₁ m₂] (u₁ - u₂)² [2(m₁ + m₂)/m₁ m₂] (u₁² - u₂²) [m₁ m₂/2(m₁ + m₂)] (u₁ - u₂)² ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The resultant of two forces P and Q (such that P > Q) acting along the same straight line, but in opposite direction, is given by P - Q P + Q Q / P P / Q P - Q P + Q Q / P P / Q ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The forces which meet at one point, but their lines of action __________ on the same plane, are Known as non-coplanar concurrent forces. None of these Do not lie Lie Either A or B None of these Do not lie Lie Either A or B ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG + Ah2 IP = Ah2 / IG IP = IG - Ah2 IP = IG / Ah2 IP = IG + Ah2 IP = Ah2 / IG IP = IG - Ah2 IP = IG / Ah2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Moment of inertia of a triangular section of base (b) and height (h) about an axis through its base, is bh3/8 bh3/4 bh3/36 bh3/12 bh3/8 bh3/4 bh3/36 bh3/12 ANSWER DOWNLOAD EXAMIANS APP
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