Problems on H.C.F and L.C.M H.C.F. of 4 x 27 x 3125, 8 x 9 x 25 x 7 & 16 x 81 x 5 x 11 x 49 is: 360 540 1260 180 360 540 1260 180 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the smallest number which when increased by 5, divisible by 6, 9, 15, 20 and 24? 344 377 366 355 344 377 366 355 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Reduce 391/667 to lowest terms . 11/13 31/45 23/37 17/29 11/13 31/45 23/37 17/29 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP H.C.F. of 391 and 667 is 23.On dividing the numerator and denominator by 23, we get :391 = 391 ¸23 = 17667 667¸ 23 29
Problems on H.C.F and L.C.M Find the greatest number which will divide 25, 73 and 97 as so to leave the same remainder in each case? 12 18 24 32 12 18 24 32 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the least number which when divided by 16, 18, 20 and 2 leaves 4 as remainder in each case , but when divided by 7 leaves no. remainder 18002 18004 18000 17004 18002 18004 18000 17004 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The traffic lights at three different road crossings change after every 48 sec., 72 sec and 108 sec.respectively .If they all change simultaneously at 8:20:00 hours,then at what time they again change 10:13:17 hrs 7:25:14 hrs 8:27:12 hrs 9:22:08 hrs 10:13:17 hrs 7:25:14 hrs 8:27:12 hrs 9:22:08 hrs ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Interval of change = (L.C.M of 48,72,108)sec.=432sec. So, the lights will agin change simultaneously after every 432 seconds i.e,7 min.12sec Hence , next simultaneous change will take place at 8:27:12 hrs.
EXAMIANS