Electrical Machines For a given torque, reducing diverter resistance of a DC series motor causes decrease in speed but armature current remains the same. decrease in speed demanding less armature current. increase in speed but armature currnet remains the same. increase in speed demanding more armature current. decrease in speed but armature current remains the same. decrease in speed demanding less armature current. increase in speed but armature currnet remains the same. increase in speed demanding more armature current. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines Voltage across the open circuited field termninals of a synchorous machine under slip test is AC of supply frequency. DC of slip frequency. DC. A modulated supply frequency AC voltage with slip frequency envelop. AC of supply frequency. DC of slip frequency. DC. A modulated supply frequency AC voltage with slip frequency envelop. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines Cogging of induction motor occurs at low voltage and when stator and rotor poles are not equal. high voltage and when stator and rotor poles are equal. high voltage and when stator and rotor poles are not equal. low voltage and when stator and rotor poles are equal. low voltage and when stator and rotor poles are not equal. high voltage and when stator and rotor poles are equal. high voltage and when stator and rotor poles are not equal. low voltage and when stator and rotor poles are equal. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines Speed of DC motor can be controlled by varying its flux oer pole. applied voltage. resistance of armature culture. all of these. its flux oer pole. applied voltage. resistance of armature culture. all of these. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines Find the number of poles required, when the frequency is 50Hz and speed of the motor is 500 rpm? 5 24 10 12 5 24 10 12 ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines R1 is the resistance of the primary winding of the transformer. The turn ratio in terms of primary to secondary is K. Then the equivalent resistance of the primary referred to secondary is R1 /K² R1 /K K×R1 K²R1 R1 /K² R1 /K K×R1 K²R1 ANSWER DOWNLOAD EXAMIANS APP
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