Problems on H.C.F and L.C.M Find the least number which when divided by 6,7,8,9, and 12 leave the same remainder 1 each case 707 505 606 404 707 505 606 404 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 3 | 6 - 7 - 8 - 9 - 12----------------------------- 4 | 2 - 7 - 8 - 3 - 4 --------------------------- 2 | 2 - 7 - 2 - 3 - 1 -------------------------- | 1 - 7 - 1 - 3 - 1 L.C.M = 3 X 2 X 2 X 7 X 2 X 3 = 504.Hence required number = (504 +1) = 505
Problems on H.C.F and L.C.M The H.C.F. of two numbers is 23 and the other two factors of their L.C.M. are 13 and 14. The larger of the two numbers is: 345 276 322 299 345 276 322 299 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Clearly, the numbers are (23 x 13) and (23 x 14). Larger number = (23 x 14) = 322.
Problems on H.C.F and L.C.M The least number of four digits which is divisible by 4, 6, 8 and 10 is? 1080 1095 1075 1085 1080 1095 1075 1085 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Express 1168/1095 in simple form? 18/17 19/18 16/15 17/16 18/17 19/18 16/15 17/16 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP To express any fraction in simple (small form), we have to find the HCF of numerator and denominator. 1095)1168(1 1095 73)1095(15 1095 ——— 0 HCF of 1095 and 1168 is 73Therefore (1168/73)/(1095/73) = 16/15
Problems on H.C.F and L.C.M The least number which when divided by 5,6,7 And 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is : 1677 1683 2523 3363 1677 1683 2523 3363 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M If LCM of two number is 693, HCF of two numbers is 11 and one number is 99, then find other 77 88 66 55 77 88 66 55 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Product of two numbers = Product of their HCF and LCMSo Other number =(693×11/99) = 77
EXAMIANS