Problems on H.C.F and L.C.M Find the least number which when divided by 6,7,8,9, and 12 leave the same remainder 1 each case 404 707 606 505 404 707 606 505 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 3 | 6 - 7 - 8 - 9 - 12----------------------------- 4 | 2 - 7 - 8 - 3 - 4 --------------------------- 2 | 2 - 7 - 2 - 3 - 1 -------------------------- | 1 - 7 - 1 - 3 - 1 L.C.M = 3 X 2 X 2 X 7 X 2 X 3 = 504.Hence required number = (504 +1) = 505
Problems on H.C.F and L.C.M Find the HCF of 54, 288, 360 19 16 18 17 19 16 18 17 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Lets solve this question by factorization method.18=2×3²,288=2×2×2×2×2×3²,360=2³×3²×5So HCF will be minimum term present in all three, i.e.2×3²=18
Problems on H.C.F and L.C.M Two numbers are in the ratio 3 : 4. If their L.C.M. is 96. what is sum of the numbers? 84 48 56 76 84 48 56 76 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the largest number which divides 62, 132 and 237 to leave the same remainder in each case. 52 22 35 48 52 22 35 48 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = H.C.F. of (132 - 62), (237 - 132) and (237 - 62) = H.C.F. of 70, 105 and 175 = 35.
Problems on H.C.F and L.C.M Product of two co-prime numbers is 117. Their L.C.M should be: equal to their H. F 117 Cannot be calculated 1 equal to their H. F 117 Cannot be calculated 1 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Which of the following integers has the most number of divisors? 101 99 176 182 101 99 176 182 ANSWER DOWNLOAD EXAMIANS APP
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