Problems on H.C.F and L.C.M Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case. 8 4 6 2 8 4 6 2 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43) = H.C.F. of 48, 92 and 140 = 4.
Problems on H.C.F and L.C.M The least number of four digits which is divisible by 15, 25, 40 and 75 is: 9000 9600 9400 9800 9000 9600 9400 9800 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M A, B and C start running around a circular stadium and complete one round in 27 s, 9 s and 36 s, respectively. In how much time will they meet again at the starting point? 3 minute 48 seconds 2 minute 48 seconds 1 minute 48 seconds 4 minute 48 seconds 3 minute 48 seconds 2 minute 48 seconds 1 minute 48 seconds 4 minute 48 seconds ANSWER EXPLANATION DOWNLOAD EXAMIANS APP LCM of 27, 9 and 36 = 108 So they will meet again at the starting point after 108 sec. i.e., 1 min 48 sec.
Problems on H.C.F and L.C.M HCF and LCM two numbers are 12 and 396 respectively. If one of the numbers is 36, then the other number is? 36 132 66 264 36 132 66 264 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M HCF of 3/16, 5/12, 7/8 is: 3/47 2/47 5/48 1/48 3/47 2/47 5/48 1/48 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The traffic lights at three different road crossings change after every 48 sec., 72 sec and 108 sec.respectively .If they all change simultaneously at 8:20:00 hours,then at what time they again change 8:27:12 hrs 7:25:14 hrs 9:22:08 hrs 10:13:17 hrs 8:27:12 hrs 7:25:14 hrs 9:22:08 hrs 10:13:17 hrs ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Interval of change = (L.C.M of 48,72,108)sec.=432sec. So, the lights will agin change simultaneously after every 432 seconds i.e,7 min.12sec Hence , next simultaneous change will take place at 8:27:12 hrs.
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