Problems on H.C.F and L.C.M Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case. 6 2 4 8 6 2 4 8 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43) = H.C.F. of 48, 92 and 140 = 4.
Problems on H.C.F and L.C.M The H.C.F. and L.C.M. of two numbers are 12 and 5040 respectively If one of the numbers is 144, find the other number 360 180 420 110 360 180 420 110 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Product of 2 numbers = product of their HCF and LCM144 * x = 12 * 5040x = (12*5040)/144 = 420
Problems on H.C.F and L.C.M The least number which is a perfect square and is divisible by each of the numbers 16,20, and 24, is : 11400 3600 6400 1600 11400 3600 6400 1600 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The wheels revolve round a common horizontal axis. They make 15, 20 and 48 revolutions in a minute respectively. Starting with a certain point on the circumference down wards. After what interval of t 2 min None 1 min 3 min 2 min None 1 min 3 min ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M What is the HCF of 2/3, 4/9 and 6/5 8/45 7/45 4/15 2/45 8/45 7/45 4/15 2/45 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is: 107 101 111 185 107 101 111 185 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numbers be 37a and 37b.Then, 37a x 37b = 4107 ab = 3.Now, co-primes with product 3 are (1, 3).So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111). Greater number = 111.
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