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Problems on H.C.F and L.C.M

Problems on H.C.F and L.C.M
Reduce 4128/4386 to its lowest terms

13/18
13/17
14/13
16/17

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The least number which is a perfect square and is divisible by each of the numbers 16, 20 and 24, is:

6400
3600
1600
14400

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
What is the least number when divided by 4, 5, 6, 8 and 10 leaves 3 as remainder?

112
121
123
116

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

 The least number which when divided by 4,5,6,8 and 10 is the LCM of these numbers. But each time  to get 3 as remainder, we have to add the remainder 3 to the obtained LCM.LCM of (4, 5, 6, 8, 10)+ 3=120+3=123

Problems on H.C.F and L.C.M
Find the largest number of four digits exactly divisible by 12,15,18 and 27.

7720
6720
8720
9720

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

The Largest number of four digits is 9999.       Required number must be divisible by L.C.M. of 12,15,18,27 i.e. 540.      On dividing 9999 by 540,we get 279 as remainder .   Required number = (9999-279) = 9720.

Problems on H.C.F and L.C.M
The H.C.F. of 0.54, 1.8 and 7.2 is:

0.018
1.8
18
0.18

ANSWER DOWNLOAD EXAMIANS APP

Problems on H.C.F and L.C.M
The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is:

10
20
40
30

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let the numbers be 2x and 3x.Then, their L.C.M. = 6x.So, 6x = 48 or x = 8The numbers are 16 and 24.Hence, required sum = (16 + 24) = 40.

MORE MCQ ON Problems on H.C.F and L.C.M

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