Find H = _____ A/m at the center of a circular coil of diameter 1 m and carrying a current of 2A

• A. 8 A/m
• B. 2 A/m
• C. 4 A/m
• D. 1 A/m

Answer: (B)

Magnetic Field Strength (H) gives the quantitative measure of strongness or weakness of the magnetic field. H = B/μo Where B = Magnetic Flux Density μo = Vacuum Permeability Magnetic Field strength at the center of circular loop carrying current I is given by B = μoI/2r B/μo = I/2r H = I/2r Where r = Radius Now Given Parameters Diameter = 1m Current = 2A ∴ Magnetic field Intensity H = (2 / 2 × 1/2) = 2 A/m