SSC JE Electrical 2019 with solution SET-1
 If dΦ is the luminous flux incident normally on an area dA, then Illuminance is given as

Φ × A
dΦ ⁄ dA
dΦ − dA
dA ⁄ dΦ

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SSC JE Electrical 2019 with solution SET-1
 The Norton’s current in the circuit shown below is

2A
120A
4A
12A

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SSC JE Electrical 2019 with solution SET-1
 If the copper loss of a transformer at half full load is 400 W, then the copper loss corresponding to full load is

400 W
1200 W
1600 W
800 W

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