DNA Structure and Replication E.coli DNA polymerases II and III lack 5' → 3' exonuclease activity partially 5' → 3' endonuclease activity 5' → 3' endonuclease activity partially 5' → 3' exonuclease activity 5' → 3' exonuclease activity partially 5' → 3' endonuclease activity 5' → 3' endonuclease activity partially 5' → 3' exonuclease activity ANSWER DOWNLOAD EXAMIANS APP
DNA Structure and Replication In DNA, there are five bases known as adenine, guanine, thymine, tryptophan and cytosine four bases known as adenine, guanine, thymine and cytosine three bases known as adenine, guanine and cytosine only two bases known as adenine and cytosine five bases known as adenine, guanine, thymine, tryptophan and cytosine four bases known as adenine, guanine, thymine and cytosine three bases known as adenine, guanine and cytosine only two bases known as adenine and cytosine ANSWER DOWNLOAD EXAMIANS APP
DNA Structure and Replication In a typical electrophoresis experiment, larger fragments of DNA move more quickly, so they appear nearer the top of a gel photograph slowly, so they appear nearer the top of a gel photograph slowly, so they appear nearer the bottom of a gel photograph quickly, so they appear nearer the bottom of a gel photograph quickly, so they appear nearer the top of a gel photograph slowly, so they appear nearer the top of a gel photograph slowly, so they appear nearer the bottom of a gel photograph quickly, so they appear nearer the bottom of a gel photograph ANSWER DOWNLOAD EXAMIANS APP
DNA Structure and Replication Deoxyribonucleoside triphosphates, being need in the chain termination methods are all of these dGTP and dCTP dATP dTTP all of these dGTP and dCTP dATP dTTP ANSWER DOWNLOAD EXAMIANS APP
DNA Structure and Replication Which enzyme catalyzes the elongation of DNA molecules? Helicase DNA polymerase Primase DNA ligase Helicase DNA polymerase Primase DNA ligase ANSWER DOWNLOAD EXAMIANS APP
DNA Structure and Replication Which of the following is used to determine the appropriate stringency (Wallace rule)? Tm = 4 x (No.of G:C base pair) + 2 x (No.of A:T base pair) Tm = 2 x (No.of G:C base pair) + 4 x (No.of A:T base pair) Tm = 69.3° + 0.41 (%)G+C -650/1 Tm = 4 x (No.of A:T base pair) + 2 x (No.of G:C base pair) Tm = 4 x (No.of G:C base pair) + 2 x (No.of A:T base pair) Tm = 2 x (No.of G:C base pair) + 4 x (No.of A:T base pair) Tm = 69.3° + 0.41 (%)G+C -650/1 Tm = 4 x (No.of A:T base pair) + 2 x (No.of G:C base pair) ANSWER DOWNLOAD EXAMIANS APP
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