Engineering Mechanics Center of gravity of a thin hollow cone lies on the axis at a height of One-fourth of the total height above base One-half of the total height above base One-third of the total height above base Three-eighth of the total height above the base One-fourth of the total height above base One-half of the total height above base One-third of the total height above base Three-eighth of the total height above the base ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The power developed by a body acted upon by a torque 'T' Newton meter (N - m) and revolving at ω radian/s is given by T.ω/4500 (in kilowatts) T.ω/75 (in kilowatts) T.ω/60 (in watts) T.ω (in watts) T.ω/4500 (in kilowatts) T.ω/75 (in kilowatts) T.ω/60 (in watts) T.ω (in watts) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics In order to determine the effects of a force, acting on a body, we must know All of these Magnitude of the force Nature of the force i.e. whether the force is push or pull Line of action of the force All of these Magnitude of the force Nature of the force i.e. whether the force is push or pull Line of action of the force ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG + Ah2 IP = IG - Ah2 IP = Ah2 / IG IP = IG / Ah2 IP = IG + Ah2 IP = IG - Ah2 IP = Ah2 / IG IP = IG / Ah2 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The periodic time (T) is given by (where, ω = Angular velocity of particle in rad/s.) 2π/ω π/ω ω/2π 2π × ω 2π/ω π/ω ω/2π 2π × ω ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The centre of percussion is below the centre of gravity of the body and is at a distance equal to kG2/h h × kG h2/kG h/kG kG2/h h × kG h2/kG h/kG ANSWER DOWNLOAD EXAMIANS APP
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