Engineering Mechanics The center of gravity of a quadrant of a circle lies along its central radius (r) at a distance of 0.7 r 0.8 r 0.5 r 0.6 r 0.7 r 0.8 r 0.5 r 0.6 r ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics Moment of inertia of a triangular section of base (b) and height (h) about an axis passing through its C.G. and parallel to the base, is bh3/8 bh3/36 bh3/4 bh3/12 bh3/8 bh3/36 bh3/4 bh3/12 ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The linear velocity of a body rotating at ω rad/s along a circular path of radius r is given by ω².r ω.r ω/r ω²/r ω².r ω.r ω/r ω²/r ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The maximum efficiency of a lifting machine is m/V.R. 1/m V.R./m 1/(m × V.R.) m/V.R. 1/m V.R./m 1/(m × V.R.) ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics The friction experienced by a body, when at rest, is known as Limiting friction Dynamic friction Static friction Coefficient of friction Limiting friction Dynamic friction Static friction Coefficient of friction ANSWER DOWNLOAD EXAMIANS APP
Engineering Mechanics According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.) IP = IG - Ah2 IP = IG / Ah2 IP = IG + Ah2 IP = Ah2 / IG IP = IG - Ah2 IP = IG / Ah2 IP = IG + Ah2 IP = Ah2 / IG ANSWER DOWNLOAD EXAMIANS APP
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