Applied Mechanics and Graphic Statics At a given instant ship ‘A’ is travelling at 6 km/h due east and ship ‘B’ is travelling at 8 km/h due north. The velocity of ‘B’ relative to ‘A’ is 1 km/hrs 7 km/hrs 10 km/hrs 2 km/hrs 1 km/hrs 7 km/hrs 10 km/hrs 2 km/hrs ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics According to Kennedy's theorem, if three bodies have plane motions, their instantaneous centers lie on A triangle Two straight lines A straight line A point A triangle Two straight lines A straight line A point ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A body A of mass 6.6 kg which is lying on a horizontal platform 4.5 m from its edge is connected to the end of a light string whose other end is supporting a body of mass 3.2 kg as shown in below figure. If the friction between the platform and the body A is 1/3, the acceleration is 1.25 m/sec² 0.75 m/sec² 0.5 m/sec² 1.00 m/sec² 1.25 m/sec² 0.75 m/sec² 0.5 m/sec² 1.00 m/sec² ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics ‘u₁’ and ‘u₂’ are the velocities of approach of two moving bodies in the same direction and their corresponding velocities of separation are ‘v₁’ and ‘v₂’. As per Newton's law of collision of elastic bodies, the coefficient of restitution (e) is given by e = v₁ - v₂/u₂ - u₁ e = v₂ - v₁/u₁ - u₂ e = v₁ - v₂/u₂ + u₁ e = u₂ - u₁/v₁ - v₂ e = v₁ - v₂/u₂ - u₁ e = v₂ - v₁/u₁ - u₂ e = v₁ - v₂/u₂ + u₁ e = u₂ - u₁/v₁ - v₂ ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A rod AB carries three loads of 30 N, 70 N and 100 N at distances of 20 mm, 90 mm and 150 mm respectively from A. Neglecting the weight of the rod, the point at which the rod will balance is 125.5 mm from A 119.5 mm from A 132.5 mm from A 109.5 mm from A 125.5 mm from A 119.5 mm from A 132.5 mm from A 109.5 mm from A ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If two bodies of masses M1 and M2(M1 > M2) are connected by alight inextensible string passing over a smooth pulley, the tension in the string, will be given by T = g(M1 - M2)/(M1 + M2) T = g(M2 - M1)/(M1 + M2) T = g(M1 + M2)/(M1 × M2) T = g(M2 + M1)/(M2 - M1) T = g(M1 - M2)/(M1 + M2) T = g(M2 - M1)/(M1 + M2) T = g(M1 + M2)/(M1 × M2) T = g(M2 + M1)/(M2 - M1) ANSWER DOWNLOAD EXAMIANS APP
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