Applied Mechanics and Graphic Statics Two forces of 6 Newtons and 8 Newtons which are acting at right angles to each other, will have a resultant of 10 Newtons 8 Newtons 12 Newtons 5 Newtons 10 Newtons 8 Newtons 12 Newtons 5 Newtons ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Parallelogram Law of Forces states, "if two forces acting simultaneously on a particle be represented in magnitude and direction by two adjacent sides of a parallelogram, their resultant may be represented in magnitude and direction by The diagonal of the parallelogram which does not pass through the point of intersection of the forces Its longer side The diagonal of the parallelogram which passes through the point of intersection of the forces Its shorter side The diagonal of the parallelogram which does not pass through the point of intersection of the forces Its longer side The diagonal of the parallelogram which passes through the point of intersection of the forces Its shorter side ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The centre of gravity of the trapezium as shown in below figure from the side is at a distance of Applied Mechanics and Graphic Statics mcq question image (h/3) × [(b + 2a)/(b + a)] (h/3) × [(2b + a)/(b + a)] (h/2) × [(b + 2a)/(b + a)] (h/2) × [(2b + a)/(b + a)] (h/3) × [(b + 2a)/(b + a)] (h/3) × [(2b + a)/(b + a)] (h/2) × [(b + 2a)/(b + a)] (h/2) × [(2b + a)/(b + a)] ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The resolved part of the resultant of two forces inclined at an angle θ in a given direction is Sum of the forces multiplied by the tangent θ° Arithmetical sum of the resolved parts of the forces in the direction Difference of the forces multiplied by cosine θ° Algebraic sum of the resolved parts of the forces in the direction Sum of the forces multiplied by the tangent θ° Arithmetical sum of the resolved parts of the forces in the direction Difference of the forces multiplied by cosine θ° Algebraic sum of the resolved parts of the forces in the direction ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A cable loaded with 0.5 tonne per horizontal metre span is stretched between supports in the same horizontal line 400 m apart. If central dip is 20 m, the minimum tension in the cable, will be 200 tonnes at the right support 500 tonnes at the centre 200 tonnes at the left support 200 tonnes at the centre 200 tonnes at the right support 500 tonnes at the centre 200 tonnes at the left support 200 tonnes at the centre ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Cartesian form of the equation of catenary is y = c cosh x/c y = c tan x/c y = c sin x/c y = c sinh x/c y = c cosh x/c y = c tan x/c y = c sin x/c y = c sinh x/c ANSWER DOWNLOAD EXAMIANS APP
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