RCC Structures Design An R.C.C. beam of 6 m span is 30 cm wide and has a lever arm of 55 cm. If it carries a U.D.L. of 12 t per m and allowable shear stress is 5 kg/cm², the beam Is safe with stirrups Is safe in shear Needs revision of section Is safe with stirrups and inclined bars Is safe with stirrups Is safe in shear Needs revision of section Is safe with stirrups and inclined bars ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design As per IS : 456, the reinforcement in a column should not be less than 0.8% and not more than 8% of cross-sectional area 0.6% and not more than 6% of cross-sectional area 0.7% and not more than 7% of cross-sectional area 0.5% and not more than 5% of cross-sectional area 0.8% and not more than 8% of cross-sectional area 0.6% and not more than 6% of cross-sectional area 0.7% and not more than 7% of cross-sectional area 0.5% and not more than 5% of cross-sectional area ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the effective length of a 32 cm diameter R.C.C. column is 4.40 m, its slenderness ratio, is 45 50 40 55 45 50 40 55 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design An R.C.C. column is treated as long if its slenderness ratio is greater than 50 40 30 35 50 40 30 35 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design According to load factor method, the permissible load ‘W’ on a short column reinforced with longitudinal bars and lateral stirrups, is Stress in steel × area of steel Stress in concrete × area of concrete None of these Stress in concrete × area of concrete + Stress in steel × area of steel Stress in steel × area of steel Stress in concrete × area of concrete None of these Stress in concrete × area of concrete + Stress in steel × area of steel ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If K is a constant depending upon the ratio of the width of the slab to its effective span l, x is the distance of the concentrated load from the nearer support, bw is the width of the area of contact of the concentrated load measured parallel to the supported edge, the effective width of the slab be is Kx (1 - x/l) + bw K/x (1 + x/d) + bw All listed here Kx (1 + x/l) + bw Kx (1 - x/l) + bw K/x (1 + x/d) + bw All listed here Kx (1 + x/l) + bw ANSWER DOWNLOAD EXAMIANS APP
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