Engineering Economics A young engineer borrowed P 10,000 at 12% interest and paid P 2,000 per annum for the last 4 years. What does he have to pay at the end of the fifth year in order to pay off his loan? P 6,292.93 P 6,999.39 P 6,922.93 P 6,222.39 P 6,292.93 P 6,999.39 P 6,922.93 P 6,222.39 ANSWER DOWNLOAD EXAMIANS APP
Engineering Economics What type of bond is issued jointly by two or more corporations? Trust bond Tie-up bond Mortgage bond Joint bond Trust bond Tie-up bond Mortgage bond Joint bond ANSWER DOWNLOAD EXAMIANS APP
Engineering Economics What is defined as the investment of loan or principal which is based not only on the original amount of the loan or principal but the amount of loaned or principal plus the previous accumulated interest? Effective rate of interest Compound interest Nominal rate of interest Simple interest Effective rate of interest Compound interest Nominal rate of interest Simple interest ANSWER DOWNLOAD EXAMIANS APP
Engineering Economics If ‘P’ is principal amount, ‘i’ is the rate of interest and ‘n’ is the number of periods in years, then the interest factor is: ni (1 + ni) None of these (ni - 1) ni (1 + ni) None of these (ni - 1) ANSWER DOWNLOAD EXAMIANS APP
Engineering Economics A man invested P110,000 for 31 days. The net interest after deducting 20% withholding tax is P890.36. Find the rate of return annually. 0.1175 0.115 0.1232 0.1195 0.1175 0.115 0.1232 0.1195 ANSWER DOWNLOAD EXAMIANS APP
Engineering Economics The declining balance method is also known as ______. Double percentage method Constant percentage method Modified SYD method Modified sinking fund method Double percentage method Constant percentage method Modified SYD method Modified sinking fund method ANSWER DOWNLOAD EXAMIANS APP