Engineering Economics A young engineer borrowed P 10,000 at 12% interest and paid P 2,000 per annum for the last 4 years. What does he have to pay at the end of the fifth year in order to pay off his loan? P 6,999.39 P 6,292.93 P 6,922.93 P 6,222.39 P 6,999.39 P 6,292.93 P 6,922.93 P 6,222.39 ANSWER DOWNLOAD EXAMIANS APP
Engineering Economics What is the term for an annuity with a fixed time span? Annuity due Annuity certain Ordinary annuity Perpetuity Annuity due Annuity certain Ordinary annuity Perpetuity ANSWER DOWNLOAD EXAMIANS APP
Engineering Economics The person desires to pay off the amount in 10 equal annual instalments. The amount of each installment is: Rs. 7738 None of these Rs. 5638 Rs. 6638 Rs. 7738 None of these Rs. 5638 Rs. 6638 ANSWER DOWNLOAD EXAMIANS APP
Engineering Economics What is the basic accounting equation? Owner’s equity = liability – assets Liability = assets + owners’ equity Owner’s equity = assets + liability Assets = liability + owner’s equity Owner’s equity = liability – assets Liability = assets + owners’ equity Owner’s equity = assets + liability Assets = liability + owner’s equity ANSWER DOWNLOAD EXAMIANS APP
Engineering Economics An asset is purchased for P 9,000.00. Its estimated economic life is 10 years after which it will be sold for P 1,000.00. Find the depreciation in the first three years using sum-of-years digit method P 3,927.27 P 3,279.27 P 3,792.72 P 3,729.27 P 3,927.27 P 3,279.27 P 3,792.72 P 3,729.27 ANSWER DOWNLOAD EXAMIANS APP
Engineering Economics What is the main reason why the sinking fund method of computing depreciation is seldom used in the industry? The initial depreciation is low The initial deprecation is high Rate of interest cannot be exactly determined Unstable economy The initial depreciation is low The initial deprecation is high Rate of interest cannot be exactly determined Unstable economy ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS