Theory of Structures A truss containing j joints and m members, will be a simple truss if m = 2j – 3 j = 2m – 3 m = 3j – 2 j = 3m – 2 m = 2j – 3 j = 2m – 3 m = 3j – 2 j = 3m – 2 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The forces in the members of simple trusses, may be analysed by Method of joints Method of sections Graphical method All of these Method of joints Method of sections Graphical method All of these ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures H V are the algebraic sums of the forces resolved horizontally and vertically respectively, M is the algebraic sum of the moments of forces about any point, for the equilibrium of the body acted upon M = 0 V = 0 H = 0 All of these M = 0 V = 0 H = 0 All of these ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures If a three hinged parabolic arch, (span l, rise h) is carrying a uniformly distributed load w/unit length over the entire span, Horizontal thrust is wl2/8h All of these S.F. will be zero throughout B.M. will be zero throughout Horizontal thrust is wl2/8h All of these S.F. will be zero throughout B.M. will be zero throughout ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The ratio of the area of cross-section of a circular section to the area of its core, is 11 16 15 14 11 16 15 14 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A lift of weight W is lifted by a rope with an acceleration f. If the area of cross-section of the rope is A, the stress in the rope is [W (2 + f/G)]/A [W (1 + f/ G)]/ A (1 – g/f)/A [W (2 + g/f)]/A [W (2 + f/G)]/A [W (1 + f/ G)]/ A (1 – g/f)/A [W (2 + g/f)]/A ANSWER DOWNLOAD EXAMIANS APP
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