Engineering Thermodynamics A mixture of gas expands from 0.03 m3 to 0.06 m3 at a constant pressure of 1 MPa and absorbs 84 kJ of heat during the process. The change in internal energy of the mixture is 54 kJ 114 kJ 30 kJ 84 kJ 54 kJ 114 kJ 30 kJ 84 kJ ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics General gas equation is PV = C PV=mRT PV=nRT PV=KiRT PV = C PV=mRT PV=nRT PV=KiRT ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics In an extensive property of a thermodynamic system Extensive work is done None of the listed here Extensive energy is utilized Extensive heat is transferred Extensive work is done None of the listed here Extensive energy is utilized Extensive heat is transferred ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics Stirling cycle consists of Two constant volume and two isentropic processes Two constant pressure and two isothermal processes One constant volume, one constant pressure and two isentropic processes Two constant volume and two isothermal processes Two constant volume and two isentropic processes Two constant pressure and two isothermal processes One constant volume, one constant pressure and two isentropic processes Two constant volume and two isothermal processes ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics The total energy of a molecule is shared equally by the various degrees of freedom possessed by it. This law is known as Law of equipartition of energy Law of conservation of energy None of the listed here Law of degradation of energy Law of equipartition of energy Law of conservation of energy None of the listed here Law of degradation of energy ANSWER DOWNLOAD EXAMIANS APP
Engineering Thermodynamics A path 1-2-3 is given. A system absorbs 100 kJ as heat and does 60 kJ of work while along the path 1-4-3, it does 20 kJ of work. The heat absorbed during the cycle 1-4-3 is -80 kJ +60 kJ -40 kJ -140 kJ -80 kJ +60 kJ -40 kJ -140 kJ ANSWER DOWNLOAD EXAMIANS APP
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