Area Problems A man walked diagonally across a square lot. Approximately, what was the percent saved by not walking along the edges? 30 33 24 20 30 33 24 20 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the side of the square(ABCD) be x metres. Then, AB + BC = 2x metres. AC = √2x = (1.41x) m. Saving on 2x metres = (0.59x) m. Saving % = ❨ 0.59x x 100 ❩% = 30%
Area Problems The length of each side of an equilateral triangle having an area of 4?3 cm 2 is? 4/?3 cm ?3/4 cm 3 cm 4 cm 4/?3 cm ?3/4 cm 3 cm 4 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of equilateral triangle = ?3/4 a2 = 4?3.? a2 = 16? a = 4 cm
Area Problems If the sides of a squares is increased by 25%, then the area of the squares will be increased by 56.25% 125% 53.75% 50% 56.25% 125% 53.75% 50% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required increment = 2a + [a2 / 100] %= 2 x 25 + [(252)/100)] %= 50 + (625/100)% = 56.25%
Area Problems If the radius of a circle be reduced by 50%. Its area is reduced by? 34.5% 31.5% 65.5% 39.5% 34.5% 31.5% 65.5% 39.5% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Original area = ? x (r/2)2 = ?r2/4Reduction in area = ? r2 - 3? r2/4? Reduction per cent = [ 3?r2/4 x 4/(?r2) x 100 ] %= 75%
Area Problems One side of a rectangular field is 4 meter and its diagonal is 5 meter. The area of the field is? 12 m2 20 m 2 4?5 m2 15 m2 12 m2 20 m 2 4?5 m2 15 m2 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Other side = ?5 2 - 42 = ? 9=3 mSo The area of the rectangular field = 4 x 3 = 12 m2
Area Problems One side of a parallelogram is 14 cm. Its distance from the opposite side is 16 cm. The area of the parallelogram is? 112 sq. cm 224 sq. cm 210 sq. cm 56? sq. cm 112 sq. cm 224 sq. cm 210 sq. cm 56? sq. cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of parallelogram = Side of parallelogram x distance from the opposite side= 14 x 16 cm2= 224 cm2
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