RL Circuits A 470Ω resistor and a coil with 125Ω inductive reactance are in parallel. Both components are across a 15 V ac voltage source. Current through the inductor is 32 mA 152 mA 12 mA 120 mA 32 mA 152 mA 12 mA 120 mA ANSWER DOWNLOAD EXAMIANS APP
RL Circuits A 12 kΩ resistor is in series with a 90 mH coil across an 8 kHz ac source. Current flow in the circuit, expressed in polar form, is I = 0.3 angle 0° mA. The source voltage, expressed in polar form, is 13.84 angle 69.4° V 12.8 angle 20.6° V 0.3 angle 20.6° V 3.84 angle 20.6° V 13.84 angle 69.4° V 12.8 angle 20.6° V 0.3 angle 20.6° V 3.84 angle 20.6° V ANSWER DOWNLOAD EXAMIANS APP
RL Circuits To increase the current in a series RL circuit, the frequency should be decreased cannot be determined without values should be increased should be constant should be decreased cannot be determined without values should be increased should be constant ANSWER DOWNLOAD EXAMIANS APP
RL Circuits The voltages in Problem 5 are measured at a certain frequency. To make the resistor voltage less than the inductor voltage, the frequency is increased decreased not a factor doubled increased decreased not a factor doubled ANSWER DOWNLOAD EXAMIANS APP
RL Circuits When the resistor voltage in a series RL circuit becomes less than the inductor voltage, the phase angle cannot be determined decreases increases is not affected cannot be determined decreases increases is not affected ANSWER DOWNLOAD EXAMIANS APP
RL Circuits If the frequency is halved and the resistance is doubled, the impedance of a series RL circuit halves doubles cannot be determined without values remains constant halves doubles cannot be determined without values remains constant ANSWER DOWNLOAD EXAMIANS APP
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