Chemical Engineering Thermodynamics Which of the following will increase the volume of a real gas by four times ? Reducing pressure to one fourth at constant temperature Reducing temperature to one fourth at constant pressure Reducing the temperature to half and doubling the pressure Doubling the absolute temperature as well as pressure of the gas Reducing pressure to one fourth at constant temperature Reducing temperature to one fourth at constant pressure Reducing the temperature to half and doubling the pressure Doubling the absolute temperature as well as pressure of the gas ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics A gas can be liquified by pressure alone only, when its temperature is __________ its critical temperature. Equal to or higher than Less than Less than or equal to More than Equal to or higher than Less than Less than or equal to More than ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics In Joule-Thomson porous plug experiment, the None of these Entire apparatus is exposed to surroundings Enthalpy does not remain constant Temperature remains constant None of these Entire apparatus is exposed to surroundings Enthalpy does not remain constant Temperature remains constant ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics At absolute zero temperature, the __________ of the gas is zero. Pressure None of these Volume Mass Pressure None of these Volume Mass ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics Gibbs-Duhem equation Applies only to binary systems None of these Finds no application in gas-liquid equilibria involved in distillation States that n₁dμ₁ + n₂dμ₂ + ....njdμj = 0, for a system of definite composition at constant temperature and pressure Applies only to binary systems None of these Finds no application in gas-liquid equilibria involved in distillation States that n₁dμ₁ + n₂dμ₂ + ....njdμj = 0, for a system of definite composition at constant temperature and pressure ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics The Maxwell relation derived from the differential expression for the Helmholtz free energy (dA) is (∂V/∂S)P = (∂T/∂P)S (∂T/∂V)S = -(∂P/∂S)V (∂S/∂P)T = -(∂V/∂T)P (∂S/∂V)T = (∂P/∂T)V (∂V/∂S)P = (∂T/∂P)S (∂T/∂V)S = -(∂P/∂S)V (∂S/∂P)T = -(∂V/∂T)P (∂S/∂V)T = (∂P/∂T)V ANSWER DOWNLOAD EXAMIANS APP
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