SSC JE Electrical 2019 with solution SET-1 When the supply to the excitation fails, the synchronous generator acts like a/an Induction generator Synchronous motor Synchronous generator Induction motor Induction generator Synchronous motor Synchronous generator Induction motor ANSWER DOWNLOAD EXAMIANS APP
SSC JE Electrical 2019 with solution SET-1 ______ Opposes the change in circuit voltage Resistance Capacitance Inductive reactance Inductance Resistance Capacitance Inductive reactance Inductance ANSWER DOWNLOAD EXAMIANS APP
SSC JE Electrical 2019 with solution SET-1 The annual load factor of a generation station is equal to (No. of units actually supplied per year) ⁄ (Max. possible demand × 8760) (No. of units actually supplied per month) ⁄ (Max. possible demand × 8760) (No. of units actually supplied per year) ⁄ (Max. possible demand) (No. of units actually supplied per year) ⁄ (Max. possible demand) (No. of units actually supplied per year) ⁄ (Max. possible demand × 8760) (No. of units actually supplied per month) ⁄ (Max. possible demand × 8760) (No. of units actually supplied per year) ⁄ (Max. possible demand) (No. of units actually supplied per year) ⁄ (Max. possible demand) ANSWER DOWNLOAD EXAMIANS APP
SSC JE Electrical 2019 with solution SET-1 A magnetic circuit is applied with a current that changes at a rate of 5 A/sec. The circuit has an inductance of 2H, then the self-induced EMF is 0.4 V −4 V −2.5 V −10 V 0.4 V −4 V −2.5 V −10 V ANSWER EXPLANATION DOWNLOAD EXAMIANS APP GivenInductance L = 2 HRate of change of current di/dt = 5 A/secSelf induced EMF = − (Rate of change of current × Inductance) = −L(di/dt)= −(5 × 2) = −10V
SSC JE Electrical 2019 with solution SET-1 Identify the important feature of a DC series motor Low starting torque High starting torque Medium starting torque Zero starting torque Low starting torque High starting torque Medium starting torque Zero starting torque ANSWER EXPLANATION DOWNLOAD EXAMIANS APP In DC series motor Torque (Ta) increase as the Square of armature current (Ia) Ta ∝ Ia2. So DC motor provides high starting torque.
SSC JE Electrical 2019 with solution SET-1 With the current direction marked in the circuit shown, the net voltage applied is V1 V2 −(V2 − V1) (V2 − V1) V1 V2 −(V2 − V1) (V2 − V1) ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Net voltage = −V2 + V1Net voltage = −(V2 − V1)
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