JAVA Threads
What will happen after compiling and running following code?class A implements Runnable{ public void run(){ System.out.println("run-a"); }}1. public class Test{2. public static void main(String... args){3. A a = new A();4. Thread t = new Thread(a);5. t.start();6. t.start();7. }8. }

run-a
None of these
Compilation fails with an error at line 6
run-a run-a
Compilation succeed but Runtime Exception

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JAVA Threads
What will be the output?class A extends Thread{ public void run(){ for(int i=0; i<2; i++){ System.out.println(i); } }}public class Test{ public static void main(String argv[]){ Test t = new Test(); t.check(new A(){}); } public void check(A a){ a.start(); }}

0 1
Compilation succeed but runtime exception
0 0
Compilation error, class A has no start method
None of these

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JAVA Threads
Predict the output:class A implements Runnable{ public void run(){ try{ for(int i=0;i<4;i++){ Thread.sleep(100); System.out.println(Thread.currentThread().getName()); } }catch(InterruptedException e){ } }}public class Test{ public static void main(String argv[]) throws Exception{ A a = new A(); Thread t = new Thread(a, "A"); Thread t1 = new Thread(a, "B"); t.start(); t.join(); t1.start(); }}

A B A B A B A B
A A A A B B B B
Compilation succeed but Runtime Exception
Output order is not guaranteed
None of these

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JAVA Threads
Analyze the following code:public abstract class Test implements Runnable{ public void doSomething() { };}

The program will not compile because it does not contain abstract methods.
The program compiles fine.
The program will not compile because it does not implement the run() method.
None of these

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